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Serggg [28]
4 years ago
6

You and your friend race on a trail that is 10 miles long. In each situation, does your friend pass you before the end of the tr

ail?
a. You have a four-mile head start and jog at 6 miles per hour. Your friend bikes at 8 miles per hour.

(options)
yes

no
Part B
You have a five-mile head start and run at 7 miles per hour. Your friend bikes at 17 miles per hour.

yes

no
Explain your answer
Mathematics
1 answer:
Sliva [168]4 years ago
7 0

For the first example given the answer would be No. you have a 4 mile head start. at the 4 mile line, your friend starts at 8 miles an hour and you start running at 6 miles an hour. basic addition should give the answer. In one hour time, you wouldve ran 6 miles plus the 4 you had as a head start, giving you the 10 miles you needed to reach the finish line. He on the other hand, Biked 8 miles in an hour time. By that time, you had just reached the finish line.

So the answer is no for the first example

For the second example the maths get bit harder. You start at the 5 mile point and you friend starts at the beginning point. You only need 5 miles to win, and your friend needs double (its actually more than double, because if it was perfectly doubled, you would tie the race. Your pace just has to be a bit more than half of his speed. his speed is 17mph. yours, by logic, needs to be even a tad bit more than 8.5mph. You need to have a faster speed than 8.5mph (8.51mph works perfectly) and you win by a hair. But when we se your example, you're only going at 7mph. A whole mile and a half behind pace. Sadly, he passes you short before winning.

The second example is YES he does pass you before the end of the trail.

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Answer:

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Step-by-step explanation:

Let x represents the number of miles at which a car rented from either company cost the same amount. Therefore, we can have the following equation:

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The the cost of the two companies equal where RC = BC. Therefore, we equate equations (1) and (2) and solve for x as follows:

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This can be confirmed for equations (1) and (2) individually by substituting for x = 50 as follows:

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<h2>Explanation:</h2><h2></h2>

The diagram is missing but I'll assume that the arc BDC is:

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If those arc are equal, then this equation is true:

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m_a_m_a [10]

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