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kodGreya [7K]
3 years ago
13

Factor the trinomial: 2x^2+13x+21

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0

Answer:

(2x + 7)(x + 3)

Step-by-step explanation:

2x² + 13x + 21

2x² + 6x + 7x + 21

2x(x + 3) +7(x + 3)

(2x + 7)(x + 3)

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Using a compass, construct an accurate copy of triangle DEF. Check that EF = 4.6 cm. ​
MaRussiya [10]

Step-by-step explanation:

construct 90° then measure 4.6 cm and draw a line from F to D

5 0
2 years ago
14.7 ml and a mass of 22.8 g
aliya0001 [1]

The density of the liquid is 1.55 g/mL.

Given the following data:

Mass of liquid = 22.8 grams

Volume of liquid = 14.7 mL

To find the density (unknown) of the liquid:

Density is mass all over the volume of a substance or an object.  Thus, density is mass per unit volume of an object.

Mathematically, the density of a substance is given by the formula;

Substituting the values into the formula, we have;

Density = 1.55 g/mL

Therefore, the density of the liquid is 1.55 g/mL.

Read more: brainly.com/question/18320053

5 0
11 months ago
A Ship travels at a steady Speed.
SpyIntel [72]

Answer:

speed=24km/h or 6.67m/s

Step-by-step explanation:

Given data:

time taken = t =43 hours

distance covered = d = 1032 km

to find:

speed of the ship = v =?

solution:

as we know that speed is defined as the distance covered by an object in unit time.Formula

speed = distance covered /time taken

speed = 1032km/43hours

speed =24km/h or in international system of units the answer is 6.67m/s

4 0
3 years ago
I need awnsers for questions 1, 3, and 5! WITH WORK PLEASE! GIVING BRAINLYST!
Crazy boy [7]

Answer:

number one is the 45 feet number three is the 12 one i think and five is 70

Step-by-step explanation:

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6 0
2 years ago
Read 2 more answers
Hello people ~
Luden [163]

Cone details:

  • height: h cm
  • radius: r cm

Sphere details:

  • radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (\sqrt{20h - h^2})^2  \  ( h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20h - h^2)  (h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20 - h) (h) ( h)

\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )

<u>apply chain rule</u>

\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0

\Longrightarrow \sf 40h-3h^2=0

\Longrightarrow \sf h(40-3h)=0

\Longrightarrow \sf h=0, \ 40-3h=0

\Longrightarrow \sf  h=0,\:h=\dfrac{40}{3}<u />

<u>maximum volume:</u>                <u>when h = 40/3</u>

\sf \Longrightarrow max=  \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )

\sf \Longrightarrow maximum= 1241.123 \ cm^3

<u>minimum volume:</u>                 <u>when h = 0</u>

\sf \Longrightarrow min=  \dfrac{1}{3} \pi (0)^2(20-0)

\sf \Longrightarrow minimum=0 \ cm^3

6 0
1 year ago
Read 2 more answers
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