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HACTEHA [7]
3 years ago
5

Helppppppp!! Meeeeeee?!!!

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
8 0
The answer is c i hope this helped
morpeh [17]3 years ago
6 0
I am pretty sure the answer is c
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Help me!!!!!!!!!!!!!!!!!!!!!!!!
mestny [16]
Step 2 a negative times a positive is a negative so the answer is -75.6
5 0
4 years ago
Read 2 more answers
The cost to park a car in a parking lot is $3.45 per hour. Maleek parked his car for 4 hours on Monday and 3 hours on Tuesday. H
Anestetic [448]

Answer:

$24.15

Step-by-step explanation:

7 0
3 years ago
10.) Write -1/6 , 5/3 , -5/6 in order from least to greatest
never [62]

Answer:

Least→Greatest

-5/6, -1/6, 5/3

Step-by-step explanation:

-5/6 =  -0.8333333333333333

-1/6 =  -0.1666666666666667

5/3 =    1.6666666666666667

6 0
3 years ago
A radio station claims that the amount of advertising per hour of broadcast time has an average of 13 minutes and a standard dev
zimovet [89]

Answer:

Z = 3.33

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 13, \sigma = 1.2

You listen to the radio station for 1​ hour, at a randomly selected​ time, and carefully observe that the amount of advertising time is equal to 17 minutes. Calculate the​ z-score for this amount of advertising time.

We have to find Z when X = 17. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 13}{1.2}

Z = 3.33

5 0
3 years ago
Pls help plz thank you
Akimi4 [234]

Answer:

14, 31, 62

Step-by-step explanation:

11 + 3 = 14

14*2 = 28

28 + 3 = 31

31*2=62

7 0
2 years ago
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