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3 years ago

12 is what percent of 10

Mathematics

2 answers:

Delicious77 [7]3 years ago

5 0

Your answer is 1.2.

I hope I helped you! :)

Ludmilka [50]3 years ago

4 0

The answer is:
12is 120% of 10.

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What is the equation of a circle with a center (-2, 3) and a radius r = 5?

qwelly [4]

The formula for the equation of a circle is:
(x - h)^2 + (y - k)^2 = r^2

(h, k) is the center.

So the equation would be:
(x + 2)^2 + (y - 3)^2 = 5^2
or
(x + 2)^2 + (y - 3)^2 = 25

6 0

3 years ago

The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian

Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

$x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }$

Then the area of isosceles right triangle will be: $A=\frac{1}{2} x^2$

Therefore the area is: $A=\frac{169}{4}$

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

$S=\frac{a}{1-r}$

Substitute $a=\frac{169}{4} \ and\ r=\frac{1}{4}$ in above formula.

$S=\frac{\frac{169}{4}}{1-\frac{1}{4}}$

$S=\frac{\frac{169}{4}}{\frac{3}{4}}$

$S=\frac{169}{3}$

Hence, the Sum of the areas of theses triangles is 169/3.

7 0

3 years ago

A professor believes the students in a statistics class this term are more creative than most other students attending the unive

djverab [1.8K]

Answer:

Correct option: B

Step-by-step explanation:

The professor can perform a One-mean t-test to determine whether the average score of the students in his class is more than the average score of all the students attending university.

A t-test will be used instead of the z-test because the population standard deviation is not provided instead it is estimated by the sample standard deviation.

The hypothesis for this test can be defined as follows:

H₀: The average score of the students in his class is not more then the entire university, i.e. μ ≤ 35.

Hₐ: The average score of the students in his class is more then the entire university, i.e. μ > 35.

Given:

$\bar x=40\\SE_{\bar x}=1.63$