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omeli [17]
3 years ago
9

How would you solve this? Are there any steps to take?

Mathematics
1 answer:
Genrish500 [490]3 years ago
7 0
You just have to find what x is. Pretend there isn't the signs and think of it as = signs. Then whatever u do on one side do it to all of them
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Please help I’m so confused 25 points and brainliest!!
il63 [147K]

Answer:

1=15.7

2:31.4

3:12.5

Step-by-step explanation:

1=5×3.14=15.71

2:5×2=10×3.14=31.42

3:39.25÷3.14=12.5

hope this helps

5 0
3 years ago
Read 2 more answers
Fill in the table of values so that this is a proportional relationship with k=3/2 X. Y. *blank*. 0 2. *blank*. *blank*. 6. -2.
xxTIMURxx [149]

Answer:

x => y

0 => 0

2 => 3

4 => 6

-2 => -3

Step-by-step explanation:

The equation of a proportional relationship is represented as y = kx,

where, k = y/x

We are given that k = ³/2

This means that, equation of the relationship therefore would be:

y = ³/2x

Use this equation to solve for each missing value on the table given:

✔️Where, y = 0, substitute y = 0 into y = ³/2x to find x:

0 = ³/2x

0 * 2 = 3x

0 = 3x

0/3 = x

x = 0

✔️Where, x = 2, substitute x = 2 into y = ³/2x to find y:

y = ³/2(2)

y = 3

✔️Where, y = 6, substitute y = 6 into y = ³/2x to find x:

6 = ³/2x

6 * 2 = 3x

12 = 3x

12/3 = x

x = 4

✔️Where, x = -2, substitute x = -2 into y = ³/2x to find y:

y = ³/2(-2)

y = -3

5 0
3 years ago
What is 3x^2-2n-5=0<br> please help me!!!
expeople1 [14]
The answer to your question is: 
It is a quadratic equation in 'x', with 'n' mistakenly typed in the second term..

Although you didn't ask for the solutions to the equation, I'm already here
so I might as well go through it and find them:

<span><u>3x² - 2x - 5 = 0</u></span>

In terms of the generic quadratic formula:
A = 3
B = -2
C = -5

Plug those into the quadratic formula, and you discover that

<u>x = -1</u>
and
<u>x = ⁵/₃</u>
7 0
3 years ago
Read 2 more answers
Omplete the statement. Round to the nearest hundredth if necessary.<br><br> 75.2 in. ≈≈ cm
salantis [7]
The total is 191.008 centimeters.
4 0
3 years ago
Which math subject is the hardest
lesya [120]

Combinatorial Enumeration. That whole class was a rollercoaster ride of mind-blowing generating functions to prove crazy things. The exam had ridiculous questions like 'count the number of cactus trees with n vertices such that etc etc etc' and you'd do three pages of terrible terrible sums and algebra. Then your final answer would be something beautiful like n/2 and you'd breath a sigh of relief and thank the math gods.

6 0
1 year ago
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