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3 years ago

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What are the square roots of the equation x^2 + 6x - 9 = 0? PLEASE HELP!!!

1 answer:

pogonyaev3 years ago

3 0

X^2+ 6x - 9 = 0

Use the quadratic formula
x = (<span><span>−b± sqrt (<span>b^2−4ac</span></span>)) / 2a
</span>
a = 1
b = 6
c = -9

x = −6± sqrt (6^2−4(1)(-9) / 2(1)
x = (−6± sqrt(72))/2

so these are your two solutions to the equation
x = 1.243
x = -7.243

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3 years ago

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