What are the square roots of the equation x^2 + 6x - 9 = 0? PLEASE HELP!!!
1 answer:
X^2+ 6x - 9 = 0Use the quadratic formula x = ( <span><span>−b± sqrt ( <span>b^2−4ac </span></span>)) / 2a </span> a = 1 b = 6 c = -9 x = −6± sqrt (6^2−4(1)(-9) / 2(1) x = (−6± sqrt(72))/2 so these are your two solutions to the equationx = 1.243 x = -7.243
You might be interested in
It is -11x + 24 because you multiply the numbers in the parentheses by 3 then collect like terms 10x +24 - 21x then you do 10x minus 24x and you get -11x+24
4 + 4 + 4 - 1 = 11? Was it supposed to be an equation? I am confused.
Start by multiplying 24*5 (PEMDAS) 24*5= 125 125-41=84
Lol do your own work. Pay attention in class, it'll pay off ;)
The domain of the graph is [2≤x≤5] (answer choice B)