From the top of a 100-ft building a man
1 answer:
Answer:
219m
Step-by-step explanation:
Since the man observes the car with angle 15 before observing in 33 degrees.
For the first observation
The angle observation gives an angle if 33 degrees with the horizontal.
It gives a triangle which I'll attach to the que,
from the first triangle
Tan 33 = 100/y
Y= 100/ tan 33
Y = 153.99m.
This is the distance from the building to the distance where it was secondly observed( 33).
To find x
tan 15 = 100/(153.99+x)
153.99 + x = 100/ tan 15
153.99 + x = 373.21
The distance between the two observed angles
X= 219m.
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Answer:
The missing statement is ∠ACB ≅ ∠ECD
Step-by-step explanation:
Given two lines segment AC and BD bisect each other at C.
We have to prove that ΔACB ≅ ΔECD
In triangle ACB and ECD
AC=CE (Given)
BC=CD (Given)
Now to prove above two triangles congruent we need one more side or angle
so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles
hence, the missing statement is ∠ACB ≅ ∠ECD
