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Ann [662]
3 years ago
12

If sin ⁡x=1/2, and 0 < x < π/2, what is cos⁡(x−π/6)?

Mathematics
1 answer:
raketka [301]3 years ago
4 0

Answer:

√ 3/ 2

Step-by-step explanation:

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What is 1/9 - 2 4/9 - 5/9
Ymorist [56]
1/9-22/9-5/9
-21/9-5/9
-26/9
3 0
3 years ago
Read 2 more answers
Bodmass<br><br>-3[2/6+8{-9/3(8-5*3)-6}]​
Vadim26 [7]

9514 1404 393

Answer:

  -361

Step-by-step explanation:

Your calculator can tell you the result. It is -361.

Start with the inner parentheses and work outward. Do multiplication and division in the order shown, left to right, before addition or subtraction.

  -3[2/6+8{-9/3(8-5*3)-6}]​

  = -3[2/6+8{-9/3(8-15)-6}]​

  = -3[2/6+8{-9/3(-7)-6}]​

  = -3[2/6+8{-3(-7)-6}]​

  = -3[2/6+8{21-6}]​

  = -3[2/6+8{15}]

  = -3[1/3+8{15}]

  = -3[1/3+120]

  = -3[361/3]

  = -361

8 0
3 years ago
A student has a savings account earning 3% simple interest. She must pay $1200 for first-semester tuition by September 1 and $12
Bingel [31]

Using simple interest, it is found that she needs to earn $2,391.07 during the summer.

<h3>Simple Interest</h3>

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

A(t) = A(0)(1 + rt)

In which:

  • A(0) is the initial amount.
  • r is the interest rate, as a decimal.

For this problem, the objective is to have <u>$1200 in 3 months = 0.25 years</u>, hence the parameters are given as follows:

A(0.25) = 1200, t = 0.25, r = 0.03.

Hence we have to solve for A(0):

A(0)(1 + 0.03 x 0.25) = 1200

A(0) = 1200/(1 + 0.03 x 0.25)

A(0) = $1,191.07.

She also needs to earn $1,200 to pay the first-semester bill on time, hence:

1200 + 1191.07 = $2,391.07.

She needs to earn $2,391.07 during the summer.

More can be learned about simple interest at brainly.com/question/16646150

#SPJ1

3 0
2 years ago
I REALLY NEED HELP ILL GIVE BRAINLEISTTT
lord [1]

Answer:

960

Step-by-step explanation:

x = 0.6x + 384

Subtract 0.6x from both sides.

0.4x = 384

Divide both sides by 0.4

x = 960

5 0
3 years ago
Read 2 more answers
For what real value of $v$ is $\frac{-21-\sqrt{301}}{10}$ a root of $5x^2+21x+v$?
Degger [83]

Answer:

v = 7

is the value for which

x = (-21 - √301)/10

is a solution to the quadratic equation

5x² + 21x + v = 0

Step-by-step explanation:

Given that

x = (-21 - √301)/10 .....................(1)

is a root of the quadratic equation

5x² + 21x + v = 0 ........................(2)

We want to find the value of v foe which the equation is true.

Consider the quadratic formula

x = [-b ± √(b² - 4av)]/2a ..................(3)

Comparing (3) with (2), notice that

b = 21

2a = 10

=> a = 10/2 = 5

and

b² - 4av = 301

=> 21² - 4(5)v = 301

-20v = 301 - 441

-20v = -140

v = -140/(-20)

v = 7

That is a = 5, b = 21, and v = 7

The equation is then

5x² + 21x + 7 = 0

6 0
3 years ago
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