Multiples of 11 between 1 and 30:
11, 22
So there are 2 numbers that are multiples of 11 in the bin. There are a total of 30 cards, so the probability is written as 2/30. Or we can simplify it to 1/15.
For the next question:
There are a total of 3 + 8 = 11 balls in the bag.
The probability of choosing a red ball is 3/11.
The probability of choosing a green ball is 8/11.
Multiply the three fractions:
3/11 * 3/11 * 8/11 = 72/1331
So the probability is 72/1331.
For the last question:
A standard deck of cards has 52 cards.
There are 4 queens and 4 kings in the deck.
Probability of choosing a queen is 4/52, and the probability of choosing a king AFTER you already chose a queen is 4/51.
Multiply the two fractions:
4/52 * 4/51 = 16/2652
So the probability is 16/2652 or 4/663
What is the quistions on your test and maybe i can help you
Answer:
r equals start fraction cap a minus p over p t end fraction
Step-by-step explanation:
Subtract the term non containing r, then divide by the coefficient of r.

Answer:
The probability is 0.857
Step-by-step explanation:
We know that:
There is a total of 440 cars
There are 63 cars with defective turn signals
There are 39 with defective tires.
Now we want to find the probability that a randomly selected car does not have defective turn signals.
If all the cars have the same probability of being selected, this probability will be equal to the quotient between the number of cars that do not have defective turn signals and the total number of cars.
We know that the total number of cars is 440
And 63 of these have defective turn signals, then the rest don't.
440 - 63 = 377 cars do not have defective turn signals.
Then the probability is:
P = 377/440 = 0.857
Answer:
<u>C. 90</u>
Step-by-step explanation: