The equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 1
<h3>Equation of a line</h3>
A line is the distance between two points
Given the equation of a line expressed as 10x + 2y = -2. Determine the slope
2y = -10x -2
y = -5x - 1
Slope of the line is -5
The equation of a line in point-slope form is y - y1 = m(x-x1)
Substitute the point and the slope of the parallel line
y - 12 = -5(x - 0)
y - 12 = -5x
y = -5x + 12
Hence the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 12
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Answer:
Step-by-step explanation:
b = 2/3
a = 7/3
b)
Cross multiply,
2b + 1 = a*(3b - 1)
2b + 1 = a*3b - 3*a
2b + 1 = 3ab- 3a
2b = 3ab - 3a - 1
2b - 3ab = -3a - 1
b(2 - 3a) = -3a - 1
Answer: 21
Step-by-step explanation:
5%x420= 21
Step-by-step explanation:
<h2>
Sum of two complementary angle is 90°</h2><h2 /><h2>
so. </h2><h2>
<R+<S =90°</h2><h2>
12x-3+7x-2=90°</h2><h2>
19x-5=90°</h2><h2>
19x=95°</h2><h2>
X= 5</h2>
<h2>
<R= 60-3=57°</h2>
