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3 years ago

I'm stumped by this question. someone help with my math homework please

Mathematics

2 answers:

Lapatulllka [165]3 years ago

8 0

The answer would be .75 after you do the math that is what your answer should be.

Gre4nikov [31]3 years ago

3 0

Answer:

Cucumber (a)

Step-by-step explanation:

30 sprouts from 40 seeds is a ration of .75

checking the info in the table:

Cucumber .75

Marigold .83

Tomato .925

Watermelon .7

To find the ration divide sprouted amount by planted amount:

Cucumber 15/20 = .75

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3 years ago

Find the missing value to the nearest hundredth cos___= 7/18

Oksana_A [137]

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3 0

3 years ago

Read 2 more answers

Hi guys, can anyone help me with this triple integral? Many thanks:)

Crank

Another triple integral. We're integrating over the interior of the sphere

$x^2+y^2+z^2=2^2$

Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

$y^2=4-x^2-z^2$

x is the inner integral so at this point we conservatively say its zero. That means y goes from $-\sqrt{4-z^2}$ and $+\sqrt{4-z^2}$

Similarly the inner integral x goes between $\pm-\sqrt{4-y^2-z^2}$

So we rewrite the integral

$\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz$

Let's work on the inner one,

$\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz$

There's no z in the integrand, so we treat it as a constant.

$=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}$

So the middle integral is

$\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy$

I gotta go so I'll stop here, sorry.

7 0

3 years ago

Read 2 more answers