We know the area of the middle rectangle is 48 (length * width). removing that rectangle leaves us with two semicircles. you can combine those semicircles to be the equivalent of one circle. the area for a circle is r^2 * pi. we know the diameter is 4 because that is where we cut the semicircles. radius is half the diameter, so r is 2. 2^2 is 4, 4* pi is 12.56. add 12.56 (area of semicircles) with 48 (area of rectangle) and we get 60.56

4 0

3 years ago

Show the reflection of the given points.Locate the points of the reflection in their proper position around the x-axis

amid [387]

Answer: I believe this is it

4 0

2 years ago

In circle F with m∠EFG=54m∠EFG=54 and EF=19

elena-14-01-66 [18.8K]

Answer:

17.907082 unit

Step-by-step explanation:

According to the Question,

Given, A circle with centre F, ∠EFG=54 and EF=19 .

length of arc EG = Radius(EF) × ∠EFG(in Radian)

We Know, 1 degree = 0.0174533 Radian
54 degree = 0.942478 Radian

length of arc EG = 19 x 0.942478 ⇔ 17.907082 unit

(For Diagram please find in attachment)

3 0

3 years ago