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luda_lava [24]
4 years ago
15

The square root of 150 is between

Mathematics
2 answers:
Montano1993 [528]4 years ago
4 0
12.2474487139 is the answer u are welcome
ANTONII [103]4 years ago
3 0
12 and 13. It's approximately 12.2
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Graph the equation y=-x. is (5,5) on the line? what is the slope of the line?
bezimeni [28]
You'll actually need to graph for the first segment
but the second part can be solved with algebra

The equation of the line is y(x)=-x

if we test the co0ordinates we can find if the point lies on the line

(5,5)
y(x)=-x

Using the x co-ordinate
y(5)= -5
y=-5

Leaving us with (5,-5)

Because (5,-5) is not (5,5)
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4 0
3 years ago
25 POINTS!! PLEASE HELP!
Anvisha [2.4K]

Answer:

The length of TQ is 14.

Step-by-step explanation:

The length of SV and VS are the same.

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4x = 16

x = 4

Similarly, the length of TS and TQ are the same.

3x + 2 = 3(4) + 12 = 14

6 0
3 years ago
The length of a parasite in experiment A is 2.5 × 10–3 inch. The length of a parasite in experiment B is 1.25 × 10–4 inch. How m
torisob [31]

We have been given that :-

The length of a parasite in experiment A is 2.5 \times 10^{-3}

The length of a parasite in experiment B is 1.25 \times 10^{-4}

Let us write the the  length of the parasite in experiment A in the exponent of -3.

1.25 \times 10^{-4}= 0.125 \times 10^{-3}

Clearly, the length of parasite in experiment A is greater than the length of parasite in experiment B.

The difference in the length is given by

2.5 \times 10^{-3} -0.125 \times 10^{-4}

=2.375 \times 10^{-3}

Therefore, the length of the parasite in experiment A is =2.375 \times 10^{-3} inches  greater than the length of the parasite in experiment B.

3 0
3 years ago
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Can someone help me please ❤️
Dmitry_Shevchenko [17]

Answer: you are in that school too?

the image is the school.

wow

Step-by-step explanation:


7 0
3 years ago
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Angle UZT is congruent to angle?
Ymorist [56]

Answer:

In order for me to help you I need to either see a photo or know more about the other angle.

Step-by-step explanation:

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3 years ago
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