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fgiga [73]
3 years ago
6

Name two quadrilateral in which all the sides have an equal length

Mathematics
2 answers:
photoshop1234 [79]3 years ago
8 0
Square and Rhombus are two.

spin [16.1K]3 years ago
7 0
A parallelogram and a rhombus or a square. Best answer. Square.
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Find the sum and product of the roots.
xz_007 [3.2K]

Answer:

sum= -3 product=-4

Step-by-step explanation:

2x^2-2x+8x-8

2x(x-1)+8(x-1)

(2x+8)(x-1)

x=-4 x=1

8 0
4 years ago
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A football field is 300ft long a sloth moving very quickly travels 60ft every 5 minutes based on this ratio how many minutes wou
Ipatiy [6.2K]

Answer:

25 minute

Step-by-step explanation:

Speed is the ratio of the total distance traveled  to the total time taken to reach this distance. The formula for speed is:

Speed = total distance / total time taken

The total distance covered by the sloth = 60 ft, and the time taken = 5 minutes, hence:

Speed = total distance / total time taken

speed of the sloth = 60 ft / 5 minutes = 12 ft per minute.

We can calculate the time taken for the sloth to travel the length of the football field (i.e. 300 ft)

speed = distance / time

12 ft/minute = 300 ft / time

time = 300 ft / (12 ft/minute)

time = 25 minute

4 0
3 years ago
Find the area. 7 cm 5 cm 5 cm 22 cm 10 cm 20 cm. HELP PLEASE!!!!​
Sever21 [200]

Answer:

770000

Step-by-step explanation:

im not sure

4 0
2 years ago
Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"
vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
7 0
4 years ago
What two numbers add up to 12 but multiply to 20
marta [7]

Answer:

I think it’s 10plus2 then u multiply

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
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