Identify the height for the function: f(t)=1/2 sec (t+2)-pi

Mathematics

1 answer:

Lesechka [4]3 years ago

7 0

The eight of the fonction is:

$\;\left(0,\dfrac{\sec(2)}{2}-\pi\right)$

You might be interested in

Plz i want the answer

Pie

Step-by-step explanation:

$x = a - b{y}^{2} \\ {y}^{2} =( a - x) \div b \\ y = \sqrt{(a - x) \div b}$

6 0

3 years ago

This is any and all vaules of the variables that satifies an equation

ki77a [65]

Answer:lic my nut

Step-by-step explanation:

8 0

4 years ago

If a new sweater sells for $53 find the total cost if you are charged 5% sales tax. Round your answer to the nearest cent

Flauer [41]

Answer:

$55.65

Step-by-step explanation:

you would find 5% of 53 which is $2.65 and then add that to your original price so 53 + 2.65 = 55.65

5 0

3 years ago

The distribution of the baggage weights for passengers using a particular airline has a mean of 19.4 lbs and a standard deviatio

cupoosta [38]

We are to find the probability that the weight of total luggage for a sample of 100 passengers is less than 2100.

The mean weight of the luggage of passengers will be 2100/100 = 21.

So we have to find the probability of the mean weight to be less than 21.

Average weight = u = 19.4
Standard deviation = 5.3

Since we are dealing with a sample of 100. We will use the standard error.

Standard error = $\frac{s}{ \sqrt{n} }= \frac{5.3}{ \sqrt{100} }=0.53$

Now we have to convert the weight to z-score

$z= \frac{x-u}{ \frac{s}{ \sqrt{n} } }$

$z= \frac{21-19.4}{0.53}=3.018$

From z table we can find the probability of z being less than 3.018 is 99.87%.

Therefore, the probability that for (a random sample of) 100 passengers, the total luggage weight is less than 2,100 lbs is 99.87%

8 0

4 years ago

Read 2 more answers

How many Triangles are needed to make a star when we connect them with their smaller acute angle

yulyashka [42]

Answer:

I think it's 5 triangle are needed to make star

8 0

3 years ago

Read 2 more answers