Answer:
Step-by-step explanation:
From the table attached,
x-intercept of the linear function is, the value of 'x' when f(x) = 0
x = 3 [x-intercept]
Function 'g' is the sum of 2 and the cube root of the sum of three time x and 1.
g(x) = ![2+\sqrt[3]{3x+1}](https://tex.z-dn.net/?f=2%2B%5Csqrt%5B3%5D%7B3x%2B1%7D)
For x-intercept,
g(x) = 0
![2+\sqrt[3]{3x+1}=0](https://tex.z-dn.net/?f=2%2B%5Csqrt%5B3%5D%7B3x%2B1%7D%3D0)
3x + 1 = (-2)³
3x + 1 = -8
3x = -8 - 1
3x = -9
x = -3
Therefore, the x-intercept of function 'f' is different or greater than the x-intercept of function g.
Answer: correct.
Step-by-step explanation:
Answer:
1..JANE FISH FIRST.
2..BEN WAS LAST.
3..20 MIN AHEAD OF RITA
4..BEN WAS 25 MIN BEHIND ALL AND 5 MIN BEHIND RITA
5..9.45 IS THE AVERAGE TIME OF 3 STUDENTS
Step-by-step explanation:
<h3>MARK AS BRAINLIAST</h3>
<h2>
Hello!</h2>
The answers are:
The possible values for x in the equation, are:
First option, ![5\sqrt[3]{3}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B3%7D)
Second option, ![\sqrt[3]{375}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B375%7D)
<h2>
Why?</h2>
To solve the problem, we need to remember the following properties of the exponents and roots:
![a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}](https://tex.z-dn.net/?f=a%5Csqrt%5Bn%5D%7Bb%7D%3D%5Csqrt%5Bn%5D%7Ba%5E%7Bn%7D%2Ab%7D%20%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D%3Da%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%5C%5C%5C%5C%28a%5E%7Bb%7D%29%5E%7Bc%7D%3Da%5E%7Bb%2Ac%7D)
Then, we are given the expression:
So, finding "x", we have:
![x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}](https://tex.z-dn.net/?f=x%5E%7B3%7D%3D375%5C%5C%5C%5C%28x%5E%7B3%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%20%3D%28375%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7B375%7D%3D%5Csqrt%5B3%5D%7B125%2A3%7D%3D%5Csqrt%5B3%5D%7B125%7D%2A%5Csqrt%5B3%5D%7B3%7D%3D5%5Csqrt%5B3%5D%7B3%7D)
Hence, the possible values for x in the equation, are:
First option,
Second option,
Have a nice day!
Start your line at y=15 and for every number on x go up one square
