Plz help me with this

Mathematics

2 answers:

forsale [732]4 years ago

5 0

Answer:

$\frac{31x}{30}$

Step-by-step explanation:

Before adding we require the fractions to have a common denominator

The lowest common denominator of 2, 5 and 3 is 30, thus

$\frac{15x}{15(2)}$ + $\frac{6x}{6(5)}$ + $\frac{10x}{10(3)}$

= $\frac{15x}{30}$ + $\frac{6x}{30}$ + $\frac{10x}{30}$

Add the numerators leaving the denominator

= $\frac{15x+6x+10x}{30}$ = $\frac{31x}{30}$

wariber [46]4 years ago

3 0

Answer: $\bold{c)\quad \dfrac{31x}{30}}$

<u>Step-by-step explanation:</u>

$\dfrac{x}{2}+\dfrac{x}{5}+\dfrac{x}{3}\\\\\text{The LCD of 2, 5, and 3 is }2\cdot 5\cdot 3=30\\\text{Multiply each term so their denominator is 30:}\\\\\\\dfrac{x}{2}\bigg(\dfrac{15}{15}\bigg)+\dfrac{x}{5}\bigg(\dfrac{6}{6}\bigg)+\dfrac{x}{3}\bigg(\dfrac{10}{10}\bigg)\\\\\\=\dfrac{15x}{30}+\dfrac{6x}{30}+\dfrac{10x}{30}\\\\\\=\dfrac{15x+6x+10x}{30}\\\\\\=\large\boxed{\dfrac{31x}{30}}$

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