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AfilCa [17]
3 years ago
15

Nadia built a robot to filter air and water efficiently. She expects the robot to filter more than 343 liters of air and water w

hile using less than 49 Joules of energy. 12A+8W > 343 represents the number of minutes the robot filters air A and water W to filter more than 343 liters of air and water. 3A+4W < 49presents the number of minutes the robot filters air and water while using less than 49 Joules of energy. Does the robot meet both of Nadia's expectations by filtering air for 20 minutes and filtering water for 15 minutes?
Mathematics
2 answers:
chubhunter [2.5K]3 years ago
5 0

12A+8W > 343 represents the number of minutes the robot filters air A and water W to filter more than 343 liters of air and water.

If the robot filters air for 20 minutes and water for 15 minutes, plugging A as 20 and W as 15, let us check if the equation is true or not.

Checking left side:

12A + 8W = 12(20) +8(15)

240+ 120 = 360

Checking right side: 343

12A+8W > 343

360>343

True.

So the robot meets the first expectation.

Let us check for second equation:

3A+4W < 49

Left side : 3A +4W = 3(20) +4(15) = 60 +60 =120

Right side is 49

comparing left and right side:

3A+4W < 49

120<49

False.

So the robot does not meet the second expectation.

9966 [12]3 years ago
5 0
The robot filters the expected amount of air and water, but it doesn’t use the expected amount of energy
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muminat

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Step-by-step explanation:

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3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
The product of a number and 7, decreased by the number is equal to 42. Find the number.
evablogger [386]

7
this is the answer, its pretty simple. I'm not sure the mathematical procedures but if you plug in 7 you get 49. Then all you got to do is subtract by 7, because the question states the number is the same. So basically,
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8 0
3 years ago
Comparing the two ratios 2/4 and 1/2<br> 2/4 is larger
kumpel [21]

Answer:

<em><u>3.5 : 7 > 1.2 : 2.5.</u></em>

Step-by-step explanation:

1. Compare the ratios 4 : 5 and 2 : 3.

Solution:

Express the given ratios as fraction

4 : 5 = 4/5 and 2 : 3 =2/3

Now find the L.C.M (least common multiple) of 5 and 3

The L.C.M (least common multiple) of 5 and 3 is 15.

Making the denominator of each fraction equal to 15, we have

4/5 = (4 ×3)/(5 ×3) = 12/15 and 2/3 = (2 ×5)/(3 ×5) = 10/15

Clearly, 12 > 10

Now, 12/15 > 10/15

Therefore, 4 : 5 > 2 : 3.

2. Compare the ratios 5 : 6 and 7 : 9.

Solution:

Express the given ratios as fraction

5 : 6 = 5/6 and 7 : 9 =7/9

Now find the L.C.M (least common multiple) of 6 and 9

The L.C.M (least common multiple) of 6 and 9 is 18.

Making the denominator of each fraction equal to 18, we have

5/6 = (5 ×3)/(6 ×3) = 15/18 and 7/9 = (7 ×2)/(9 ×2) = 14/18

Clearly, 15 > 14

Now, 15/18 > 14/18

Therefore, 5 : 6 > 7 : 9.

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Solution:

1.2 : 2.5 = 1.2/2.5 and 3.5 : 7 =3.5/7

1.2/2.5 = (1.2 ×10)/(2.5 ×10 ) = 12/25 and 3.5/7 = (3.5 ×10)/(7 ×10) = 35/70 = 1/2

[We removed the decimal point from the ratios now, we will compare the ratio]

Now find the L.C.M (least common multiple) of 25 and 2

The L.C.M (least common multiple) of 25 and 2 is 50.

Making the denominator of each fraction equal to 50, we have

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Now, 25/50 > 24/50

Therefore, 3.5 : 7 > 1.2 : 2.5.

4 0
3 years ago
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zloy xaker [14]

Answer: C

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8 0
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