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The solution to the given differential equation is yp=−14xcos(2x)
The characteristic equation for this differential equation is:
P(s)=s2+4
The roots of the characteristic equation are:
s=±2i
Therefore, the homogeneous solution is:
yh=c1sin(2x)+c2cos(2x)
Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:
yp=Axsin(2x)+Bxcos(2x)
If you take the second derivative of the equation above for yp , and then substitute that result, y′′p , along with equation for yp above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side, sin(2x) , you will find:
A=0
B=−14
Therefore,
yp=−14xcos(2x)
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Answer:
x = 9
Step-by-step explanation:
The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is
5(x - 6 + 5) = 4(x - 3 + 4)
5(x - 1) = 4(x + 1) ← distribute parenthesis on both sides
5x - 5 = 4x + 4 ( subtract 4x from both sides )
x - 5 = 4 ( add 5 to both sides )
x = 9
I believe it is b)
Because you always do rise over the run and if it goes right then it is positive and if it goes left it is negative.
Answer:
y = -9/10x + 3/10 or y = 3/10(1 - 3x)
Step-by-step explanation:
Perpendicular lines have slopes that are negative reciprocals of one another
so slope of line w is -9/10
Using (-3,3) >> y = -9/10x + b
3 = -9/10(-3) + b
3 = 27/10 + b
b = 3 - 27/10 = 30/10 - 27/10 = 3/10
y = -9/10x + 3/10 or y = 3/10(1 - 3x)