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Angelina_Jolie [31]
3 years ago
12

What is the difference between individual adaptation and species adaptation?

Biology
1 answer:
Tpy6a [65]3 years ago
5 0

Answer:

Individual adaptation means the adaptations acquired by individuals during their lifetime or behaviors sharpened by experience. Species adaptation means the adaptation of species as a whole to their environments by the process of natural selection.

Explanation:

Adaptation means any change in an organism that increases the efficiency of that organism and gives a better chance to survive and reproduce. The changes may be developmental, anatomical, behavioral or physiological.

Individual adaptation means the adaptations acquired by individual organisms during their lifetime (muscles strengthened by exercise) or behaviors sharpened by experience. It is a short-term change in response to conditions with a short-term benefit. For example, on a hot day, the production of sweat increases to cool our bodies. Adaptations achieved by individuals cannot be passed on to their offspring, except in the form of learned behavior.

Species adaptation means the adaptation of species as a whole to their environments, which occur as a result of natural selection (survival of the fittest). Highly adapted species are better suited to their particular environment than a less-adapted species but less likely to survive changes to that environment while less-adapted species are well-suited to survive changes in that environment. For example, a highly adapted flowering plant species depend on a specific insect that exists only in its present environment for pollination and if that specific insect species become extinct, the plants will also cease to exist.

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By using the rule of 70 formula we can determine is Growth rate .

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The number of of years it takes for a country economy to double in size is equal to 70 divided by the growth rate in percent.

The rule 70 determines the number of years it takes for a variable to double by dividing the number 70 by the variables growth rate.

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2 years ago
Could somebody help me please? I would appreciate it...
sergejj [24]

Answer:

C. I'm pretty sure or it's D

Explanation:

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4 years ago
The kinetics analyses of an enzyme are measured as a function of substrate concentration in the presence and in the absence of 2
Aleksandr-060686 [28]

Answer:

take the reciprocal of the values as 1/S and 1/V and plot the values on lineweaver-burk plot.

so the re-arranged data is as following

1/S               1/V (no inhibitor)       1/V (with inhibitor)

0.333           0.096                       0.244

0.2              0.068                         0.156

0.1               0.044                         0.088

0.033          0.029                        0.044

0.011            0.024                         0.029

and the plotted lineweaver-burk plot with the equation of straight line would be....

where, first line represents the velocity of reaction with no inhibitor and second line represent the velocity in presence of inhibitor. X-axis has the substrate concentration as 1/S and y-axis has the velocity as 1/V.

as per the plot, equation of line on the lineweaver-burk plot, Y = mx + c, where c = 1/Vmax and m = Km/Vmax.

so solve for the given equations.

First, equation of line in the absence of inhibitor is Y = 0.23x + 0.021

so Vmax = 1/0.021 = 47.6 micromol/min

and Km/Vmax = 0.23, or Km = 0.23 x 47.6

Km = 10.95

Km do not have a unit, so 10.95 x 10-6 or as per your values round it up to 1 decimal point as 1.1 x 10-5

so value of Vmax = 47.6micromol/min and Km = 1.1 x 10-5 in the absence of inhibitor.

similarly, equation of line in the presence of inhibitor is given as Y = 0.67x + 0.021

so Vmax = 1/0.021 = 47.6 micromol/min

and Km/Vmax = 0.67

or Km = 0.67 x Vmax = 0.67 x 47.6 = 31.89

Km do not have a unit, so 31.89 x 10-6 or 3.1 x 10-5

so value of Vmax = 47.6micromol/min and Km = 3.1 x 10-5 in the absence of inhibitor.

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Answer: C!! :)

Explanation:

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