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sertanlavr [38]
3 years ago
10

−2(x − 3) = 2(x + 1) who can solve this?

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0
this answer is this right here x=1
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Write an equation in slope-intercept form that has a slope of 3 and a y-intercept of 6
podryga [215]
Y=3x+6

y=mx+b 3 is slope and m is also the slope, six is b because it’s where it BEgins :)
6 0
3 years ago
PLEASE HELP ITS DUE TODAY AND THIS IS MY LAST QUESTION
exis [7]

Answer:

Left: The substance is decreasing by 1/2 every 12 years

Right: The substance is decreasing by 5.61% each year

Step-by-step explanation:

exponential decay

A = P(1-r)ᵇⁿ, where A is the final amount, P is the initial amount, r is the rate decreased each time period, b is the number of years, and n is the number of times compounded each year

let's write each formula in terms of this

left:

f(t) = 600(1/2)^(t/12)

matching values up...

A = P(1-r)ᵇⁿ

A = f(t)

P = 600

1 - r = 1/2 -> r = 1/2

t/12 = bn -> b = number of years = t, so bn = b/12 -> n = 1/12. Thus, it is compounded 1/12 times each year, so it is compounded every t*12 = 12 years. If it was compounded each month, it would be compounded 12 times a year

Thus, this is decreasing by a rate of 1/2 each 12 years

right:

f(t) = 600(1-0.0561)^(t)

matching values up...

A = P(1-r)ᵇⁿ

A = f(t)

P = 600

1 - r = 1 - 0.0561 -> r = 0.0561 = 5.61%

t = bn -> b = number of years = t, so bn = b -> n = 1. Thus, it is compounded annually (1 time each year)

Thus, this is decreasing by a rate of 5.61% each year

8 0
2 years ago
when graphed on a coordinate plane, Bumby avenue can be represented by the equation y=-4x-7. Primrose Avenue can be represented
erastova [34]

Answer:

Bumby Avenue is represented by the line:

y = -4*x - 7.

Primrose Avenue can be represented with:

8x + 2y = 17.

We may want to find the point where both avenues intersect.

Let's isolate y in this second equation:

2y = 17 - 8x

y = 17/2 - 8x/2 = -4*x + 17/2

Now we can see that the equation for Primrose Avenue has the same slope than the equation for Bumby Avenue, and when two linear equations have the same slope, means that the lines are parallel.

Then we can conclude that Primrose Avenue and Bumby Avenue are parallel, so they never meet eachother.

7 0
3 years ago
(12a^(2) - 3)/(2)*(2a + 1)^(-2)*((6)/((2a + 1)))^(-1)
Elena L [17]

Answer:

\frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

Step-by-step explanation:

\frac{(12a^2-3)}{2*(2a+1)^{-2}}*\frac{6}{(2a+1)^{-1} }\\ = \frac{(12a^2-3)}{2 * \frac{1}{(2a+1)^{2} }} * \frac{6}{\frac{1}{2a+1}  }\\ =\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}\\=\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}

= \frac{(12a^2-3)(4a^{2} + 1 + 2 (2a)(1))}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{1} * \frac{3}{2a+1}\\= \frac{3(12a^2-3)(4a^{2} + 1 + 4a)} {2a+1}\\\\= \frac{3(12a^2(4a^{2} + 1 + 4a) - 3 (4a^{2}+1+4a)} {2a+1}\\= \frac{3(48a^{4}+12a^{2}+48a^{3}  - 12a^{2} -12 - 4a)} {2a+1}\\= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a)} {2a+1}

= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a} {2a+1}\\= \frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

6 0
4 years ago
F(x)= \frac{ \sqrt{x-6} }{ \sqrt{x-4}
Bingel [31]

Answer:

Hi!

Step-by-step explanation:

i would love to help you, but i don't quite understand the question.

Could you please tell me so i can better help you?

8 0
3 years ago
Read 2 more answers
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