Determine in which direction the parabola opens y=-3x^2+5x+11 up down left right
2 answers:
We have that
y=-3x²<span>+5x+11
we know that
the equation of the parabola in standard form can be expressed in one of the following two ways
y=ax</span>²+bx+c
<span>the parabola opens up if a is positive and opens down if a is negative
and
x=ay</span>²+by+c
the parabola opens right if a is positive and opens left if a is negative
<span>
in this problem
the equation is of the form
</span>y=ax²+bx+c<span>
a=-3
so
the parabola opens down
using a graph tool
see the attached figure
the vertex of a parabola is a maximum
the answer is
</span>the parabola opens down
y=-3x²<span>+5x+11
we know that
the equation of the parabola in standard form can be expressed in one of the following two ways
y=ax</span>²+bx+c
<span>the parabola opens up if a is positive and opens down if a is negative
and
x=ay</span>²+by+c
the parabola opens right if a is positive and opens left if a is negative
<span>
in this problem
the equation is of the form
</span>y=ax²+bx+c<span>
a=-3
so
the parabola opens down
using a graph tool
see the attached figure
the vertex of a parabola is a maximum
the answer is
</span>the parabola opens down
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