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melomori [17]
4 years ago
8

Which 2 equivalent fractions are shown on these number line?

Mathematics
1 answer:
nevsk [136]4 years ago
5 0

Answer:

2 equivalent fractions :

1/2 = 2/4

2/3 = 4/6

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Explain the advantages and disadvantages of each payment method.
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$ 110 he had 185 in his account then he needs to take away 75 from his account
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21 laps in 7 minutes how long did it take to run one lap​
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Answer: It takes 1/3 of a minute for each lap

Step-by-step explanation:

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3 years ago
The population of a city has decreased by 33% since it was last measured. If the current population is 20,100, what was the prev
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2 years ago
In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead. Construct a 95% conden
S_A_V [24]

Answer:

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead.

This means that n = 42, \pi = \frac{26}{42} = 0.619

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 - 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.472

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 + 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.766

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

4 0
3 years ago
Cereal. A dietician obtains the amounts of sugar (incentigrams) from 100 centigrams (or 1 gram) in each of 10 differentcereals,
nadezda [96]

Answer:

Range is 44

mean is 29.7

variance is 289.56

standard deviation is 17.016

Step-by-step explanation:

The data given as follows

3, 24, 30, 47, 43, 7, 47,13, 44, 39

Range = maximum - minimum

             = 47 -3 = 44

mean = \frac{3+24+30+47+43+7+47+13+44+39}{10} = 297/10 = 29.7

variance = \frac{sum xi^2 }{N} - mean^2 }

              = 289.56

SD = \sqrt{variance}  = 17.016

The standard deviation of the given data is not a good measure as the range and standard deviation are far apart. The standard deviation gives how the given data is dispersed from the mean or expected value, while the range gives a rough idea of variability of the data.

3 0
3 years ago
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