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2 years ago

Show me how to write the first five terms of a pattern that begins with 20

Mathematics

1 answer:

erica [24]2 years ago

3 0

20,40,60,80,100,102 just continue from there

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If g(x) = 3 - 2x find, g(-1)

pogonyaev

Steps to solve:

g(x) = 3 - 2x when g(-1)

~Substitute

g(-1) = 3 - 2(-1)

~Simplify

g(-1) = 3 - (-2)

~Simplify

g(-1) = 3 + 2

~Add

g(-1) = 5

Best of Luck!

3 0

3 years ago

Does the scatter plot 11

GarryVolchara [31]

Answer: no correlation .C

Step-by-step explanation: there is no correlation if the change on X has no impact on Y

hope this helped

5 0

1 year ago

On the first visit to the veterinarian's office, Cora's kitten weighed 550 grams. On the second visit, the kitten had gained 350

STALIN [3.7K]

Answer:

Step-by-step explanation:

total increase=350+300=650

$percentage~increase=\frac{650}{550} *100\\\approx 118.18 %%$

7 0

3 years ago

Add polynomials: (3 – 4x + 8x2) + (–6 + 2x – 5x2)

Ierofanga [76]

Answer:

The sum of the polynomials in the equation is 3x² - 2x - 3

Step-by-step explanation:

(3 - 4x + 8x²) + (-6 + 2x - 5x²)

Distribute the positive sign to (-6 + 2x - 5x²). So all of these terms will stay the same and maintain their original signs.

3 - 4x + 8x² - 6 + 2x - 5x²

Combine like terms.

- 3 - 2x + 3x²

Now put the equation in standard form. This means that the exponential numbers will be ordered in descending order.

3x² - 2x - 3

8 0

2 years ago

Read 2 more answers

If 5% of all vehicles travel less than 39.15 m/h and 10% travel more than 73.23 m/h, what are the mean and standard deviation of

Fantom [35]

Answer:

Standard deviation = 11.30 m/h

Mean = 57.74 m/h

Step-by-step explanation:

Assume that the travel speed is normally distributed.

The corresponding z-score to the 5th and 90th percentile of normal distribution are, respectively, -1.645 and 1.282.

For any given speed X, the z-score is:

$z= \frac{X-\mu}{\sigma}$

If z = -1.645 for X = 39.15 and z= 1.282 for X=72.23, the following system can be solved for the mean and standard deviation of vehicle speed:

$-1.645= \frac{39.15-\mu}{\sigma}\\1.282= \frac{72.23-\mu}{\sigma}\\\\-1.645 -1.282 = \frac{39.15-72.23}{\sigma} \\\sigma=11.30\ m/h\\\mu =72.23-(1.282*\sigma)\\\mu=57.74\ m/h$

The standard deviation is 11.30 m/h and the mean is 57.74 m/h.

3 0

3 years ago