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stealth61 [152]
3 years ago
11

Show me how to write the first five terms of a pattern that begins with 20

Mathematics
1 answer:
erica [24]3 years ago
3 0
20,40,60,80,100,102 just continue from there
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Simplify: (5x2 - 3x - 4)(3x - 7) A. 15x3 - 44x2 + 9x - 28 B. 15x3 - 44x2 + 9x + 28 C. 15x3 + 26x2 - 33x - 28 D. 15x3 - 26x2 - 33
pochemuha

Answer:

A. 15x^3 -44x^2 +9x +28

Step-by-step explanation:

(5x^2 -3x -4)(3x - 7)

first, distribute by multiplying the terms in each parenthesis with each other:

(5x^2 * 3x) - (3x * 3x) - (4 * 3x) - (5x^2 * 7) + (3x * 7) + (4 * 7)

simplify:

15x^3 -35x^2 -9x^2 +21x -12x +28

Now combine like terms:

15x^3 -44x^2 +9x +28

8 0
3 years ago
Two similar cones have volume of 4 m and 108 m respectively. If the large one has surface area 54 m, find the surface area of th
trasher [3.6K]

 

\displaystyle\bf\\Explanations:\\\\The~similarity~ratio~of~two~similar~cones=k\\\\k=is~the~ratio~between~2~corresponding~lengths\\\\k=\frac{R_1}{R_2}=\frac{h_1}{h_2}\\\\The~ratio~between~2~corresponding~areas~of~similar~cones=k^2\\\\\frac{Area~1}{Area~2}=k^2\\\\The~ratio~between~the~volumes~of~the~2~similar~cones=k^3\\\\\frac{Volume~1}{Volume~2}=k^3

.

\displaystyle\bf\\Solving:\\\\Volume1=108~m^3\\\\Volume2=4m^3\\\\k^3=\frac{108}{4}\\\\k^3=27~~\Big|\sqrt{~}\\\\k=\sqrt[\b3]{27}\\\\k=3\\\\Area1=54~m^2\\\\\frac{Area~1}{Area~2}=k^2\\\\\frac{54}{Area~2}=3^2\\\\\frac{54}{Area~2}=9\\\\Area2=\frac{54}{9}\\\\\boxed{\bf Area2=6 m^2}

 

4 0
3 years ago
two boxes of identical birthday candles are pictured: a 2 ounces box and 6- ounces box. There is 96 candles in the large box. Ho
Sladkaya [172]

Answer:  There are 32 candles in the small box.

Step-by-step explanation:

Since we have given that

Size of small box= 2 ounces

Size of large box = 6 ounces

Number of candles in large box = 96,

We need to find the number of candles in the small box ,

As there is direct variation between the small box and large box ,

let the number of candles in the small box be x

So,

\frac{96}{6}=\frac{x}{2}\\\\16=\frac{x}{2}\\\\16\times 2=x\\\\32=x

so, there are 32 candles in the small box.

7 0
3 years ago
Simplify: x + x + x + x + x + 2x *
Yuki888 [10]

Answer:

7x

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Over the interval [0,2pi), what are the solutions to cos(2x) = cos(x)? check all that apply​
kykrilka [37]

\cos(2x)  =  \cos(x)

Solution (1)

2x = x + 2k\pi

2x - x = 2k\pi

x = 2k\pi

for k=0 / for k=1 / for k=-1

x=0 / x=2π / x=-2π

acc / acc / rej

solution (2)

2x =  - x  + 2k\pi

2x + x = 2k\pi

3x = 2k\pi

x =  \frac{2k\pi}{3}

for k=0 / for k=1 / for k=-1

x=0 / x=2π/3 / x=-2π/3

acc / acc / rej

Note that i'm trying values of K which make the answer belong to our interval;

So our solution which i will represent as a set is;

S € {0,2π/3,2π}

6 0
2 years ago
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