Answer:
A. Perimeter of the square = 5s + 2
B. Perimeter of the rectangle = 8s + 8
C. Sum of the perimeters if s = 5: 75
D. Different between the perimeters if s=7: 27
Step-by-step explanation:
This problem is asking you to use expressions to first calculate the perimeters of two figures with a variable expression, then calculating the exact value of the perimeters when given the value of the variable. For A, the perimeter of a square is the sum of all four sides, since the sides of a square are all equal. You can find the answer by taking the given expression (5s + 2/4) and multiplying by 4 which gives you 5x +2. For B, the perimenter of a rectangle is found by again adding up all the sides, however in a rectangle the opposite sides are equal, so the widths and lengths are the same. In this case, we can take each expression and multiply by 2 and then add them together: 2(s + 9) + 2(3s -5) = 2s + 18 + 6s -10 = 8s +8. For C, when given the value of s = 5, we can then substitute this number for 's' in both expressions: 5(5) + 2 = 27 and 8(5) + 8 = 48; 27 + 48 = 75. For D, when given the value of s = 7, we can then subsitute this number for 's': 5(7) + 2 = 37 and 8(7) + 8 = 64; 64 - 37 = 27.
