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Rama09 [41]
3 years ago
12

Which systems of equations have exactly one solution?

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0
1.
y=2x \\ y=2x+1 \\ \\
2x=2x+1 \\
2x-2x=1 \\
0=1 \\
not \ true - no \ solution

2.
x=5 \\
y=-4 \\
already \ solved - one \ solution

3.
y=x+6 \\
y-6=x \\ \\
y=x+6 \\
y=x+6 \\ \\
x+6=x+6 \\
x-x=6-6 \\
0=0 \\
true - infinitely \ many \ solutions

4.
y=3x+4 \\
y=3 \\ \\
3=3x+4 \\
3-4=3x \\
-1=3x \\
x=-\frac{1}{3} \\ \\
(x,y)=(-\frac{1}{3},3) - one \ solution

The answer is 2 and 4.
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<u>See below:</u>

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Now Find the value of x of this equation.

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\sf  \implies \: x =  \cfrac{180 { {}^{ \circ} }}{12}

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Multiply each ratio given by 15 which is the value of x we got.

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\therefore \sf\implies \: First \: Angle = 5 \times 15  {}^{ \circ}  = \boxed{75 {}^{ \circ}}

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Hence,the measurements of the angles of the triangle would be 75°[First Angle],60°[Second angle],and 45° [Third Angle].

\rule{225 pt}{2pt}

I hope this helps!

Let me know if you have any questions.

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