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3 years ago

In the expression 7 to the power of 3 identify the base and the exponent.

Mathematics

1 answer:

fomenos3 years ago

6 0

7^3
base is 7
exponent is 3

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3 years ago

What is 1 4/5 + 2 3/20 +5/ 3

sveticcg [70]

$1 \frac{4}{5} +2 \frac{3}{20} + \frac{5}{3} \\ \\ 3 + \frac{4}{5} + \frac{3}{20} + \frac{5}{3} \\ \\ LCD = 60 \\ \\ 3 + \frac{4 \times 12}{5 \times 12} + \frac{3 \times 3}{20 \times 3} + \frac{5 \times 20}{3 \times 20} \\ \\ 3 + \frac{48}{60} + \frac{9}{60} + \frac{100}{60} \\ \\ 3 + \frac{48 + 9 + 100}{60} \\ \\ 3 + \frac{157}{60} \\ \\ 3 + 2 \frac{37}{60} \\ \\ 5 \frac{37}{60} \\ \\ Answer: \fbox {5 37/60} \ or \ \fbox {5.6167}$

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3 years ago

In a certain Algebra 2 class of 29 students, 7 of them play basketball and 14 of them

Mariulka [41]

Answer:

<em>Two possible answers below</em>

Step-by-step explanation:

<u>Probability and Sets</u>

We are given two sets: Students that play basketball and students that play baseball.

It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.

This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

$\displaystyle P=\frac{19}{29}$

P = 0.66

Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:

We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.

Thus, there 19-2=17 students who play only one of the sports. The probability is:

$\displaystyle P=\frac{17}{29}$

P = 0.59

3 0

3 years ago