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denis-greek [22]
3 years ago
8

Can someone help me with this problem?????

Mathematics
1 answer:
snow_tiger [21]3 years ago
7 0

The perimeter is composed of two straight parts and two semicircles. We can use this to break down the problem.

We can find the straight parts easily. They are given in the problem.

straight parts: 82 x 2 = 164 m

The two semicircles make a circle. We just have to find the circumference of a circle with a diameter of 66 cm to get the length of the semicircles.

semicircles: 2(π)(66/2) = 66(3.14) = 207.24 m

answer: 164+207.24 = 371.24 m

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Answer:

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Step-by-step explanation:

We are given that BP is the perpendicular bisector of AC. QC is the perpendicular bisector of BD. AB = BC = CD.

Suppose BP = 16 cm and AD = 90 cm.

As, it is given that AD = 90 cm and the three sides AB = BC = CD.

From the figure it is clear that AD = AB + BC + CD

So, AB = \frac{90}{3} = 30 cm

BC = \frac{90}{3} = 30 cm

CD = \frac{90}{3} = 30 cm

Since the triangle, BPC is a right-angled triangle as \anglePBC = 90°, so we can use Pythagoras theorem in this triangle to find the length of the side PC.

Now, the Pythagoras theorem states that;

\text{Hypotenuse}^{2} = \text{Perpendicular}^{2} +\text{Base}^{2}

\text{PC}^{2} = \text{BP}^{2} +\text{BC}^{2}

\text{PC}^{2} = \text{16}^{2} +\text{30}^{2}

\text{PC}^{2} = 256+900 = 1156

\text{PC}=\sqrt{1156}

PC = 34 cm

Hence, the length of the side PC is 34 cm.

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