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3 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question.

Mathematics

1 answer:

inn [45]3 years ago

3 0

Answer:

Step-by-step explanation:

(a) MEAN = £fx/ fx (The sum of the all jerseys number/ number of jerseys)

= 680/11

= 61.8

(b) MEDIAN = The middle number when all the items are arranged either in ascending order or descending order

= 6, 14, 50, 51, 54, 68, 77, 78, 89, 94, 99

= 68

(Strike out the numbers, the middle number left is the median)

From those items, THERE IS NO MODE.

All the items (numbers) appeared once

(d) MID-RANGE:

This is the sum of the least valued number and the greatest valued number and dividee by two

Mid-range = (99 + 6) / 2

= 105/2

= 52.5

(e). The results tells us that:

The mean and median give two different interpretations of the average (or typical) jersey number, while the midrange shows the spread of possible jersey numbers

Also, pls note that the median implies the measure of the middle of the sets of jerseys number. And the mean tells us the distribution of the sets of jerseys number.

Hope this helped!

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Nutka1998 [239]

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Step-by-step explanation:

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2 years ago

. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?

UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

<u /> $Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \ of\ I-pad}$

$5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2$

a) Thus, the total width of the I-Pads are 61.2 inches.

$Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \ of\ Kindles}$

$4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4$

b) Thus, total width of the Kindles are 38.4 inches.

Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches

Combined number of observations = 12 + 8 =20

Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles $\div$ Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = $\frac{99.6}{20} =4.98\ inches$

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

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3 years ago

Plesae urgent hurryy for brainlist !!!!!!!!!!!

kirill [66]

C, or 5000(0.9)t is correct.

Multiplying by 0.1 would not make the car’s price go down by ten percent, but 90. Hence, C is correct.

Hope this helps!

5 0

2 years ago

Can someone tell me how to do this! #2 & #4

torisob [31]

2) The area is 1.1 m^2 because to find the area the formula is width*length. SO you would separate it. It would be 0.9 * 1 = 0.9 and 0.4 * 0.5 = 0.2. Then you add it together. So it would be 1.1 m^2. The perimeter is all the sides added together so 4.2 m, but it says mm so you have to convert it and you get 4200.
4) Area is 1.16 cm^2. Again you would seperate it. So, 1 * 1 = 1 and .2 * .8 = .16. Then you add it together and get 1.16 cm^2. The perimeter is all the sides added up. You get 4.2 cm.

8 0

3 years ago

Read 2 more answers

At a local department store sweaters typically cost $44. However due to a special the sweaters are reduced to $22. What percent

kvasek [131]

Answer:

50% reduction in price

Step-by-step explanation:

can be determined by 44- (44× X) solve for x and you get x as .5

8 0

3 years ago

Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question.

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question.