Question

Find the slope of the line through each pair of points

Answer 1

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

95)

$(-13,\ -10)\to x_1=-13,\ y_1=-10\\(16,\ 16)\to x_2=16,\ y_2=16$

substitute:

$m=\dfrac{16-(-10)}{16-(-13)}=\dfrac{16+10}{16+13}=\dfrac{26}{29}$

96)

$(6,\ -16)\to x_1=6,\ y_1=-16\\(-15,\ 9)\to x_2=-15,\ y_2=9$

substitute:

$m=\dfrac{9-(-16)}{-15-6}=\dfrac{25}{-21}=-\dfrac{25}{21}$

97)

$(12,\ -11)\to x_1=12,\ y_1=-11\\(14,\ -12)\to x_2=14,\ y_2=-12$

substitute:

$m=\dfrac{-12-(-11)}{14-12}=\dfrac{-12+11}{2}=-\dfrac{1}{2}$

OK. I think you already know how to solve it. I will give short solutions now.

98)

$m=\dfrac{15-(-3)}{8-(-14)}=\dfrac{18}{22}=\dfrac{9}{11}$

99)

$m=\dfrac{3-(-5)}{-7-3}=\dfrac{8}{-10}=-\dfrac{4}{5}$

100)

$m=\dfrac{-8-8}{-11-0}=\dfrac{-16}{-11}=\dfrac{16}{11}$

101)

$m=\dfrac{13-(-5)}{-13-(-13)}=\dfrac{18}{0}!!!-\boxed{NOT\ EXIST}$

102)

$m=\dfrac{18-1}{-10-2}=\dfrac{17}{-12}=-\dfrac{17}{12}$

103)

$m=\dfrac{19-14}{7-(-17)}=\dfrac{5}{24}$

104)

$m=\dfrac{12-0}{-6-4}=\dfrac{12}{-10}=-\dfrac{6}{5}$