if it is under 10 it will always be in the thousandths decimal place
Answer:
a) a^6+6a^4b+15a^2b^2+20b^3+15(b^4/a^2)+6(b^5/a^4)+(b/a)^6
b) 20
c) a^6+6a^4+15a^2+20+15/a^2+6/a^4+1/a^6
Step-by-step explanation:
(a+b/a)^6=a^6+6a^5(b/a)+15a^4(b/a)^2+20a^3(b/a)^3+15a^2(b/a)^4+6a(b/a)^5+(b/a)^6
a^6+6a^4b+15a^2b^2+20b^3+15(b^4/a^2)+6(b^5/a^4)+(b/a)^6
b) the coefficient of b^3=20
c) if b=1, the expression is
a^6+6a^4+15a^2+20+15/a^2+6/a^4+1/a^6
Answer:
(7) The value of -j is 9.
(8) The value of -(-j) is -9.
(9) The value of (-j)(-j) is 81.
Step-by-step explanation :
<u>Part 7:</u>
Given algebraic expression is:
j = -9
Now we have to determine the value of (-j).
-j = - (-9) = 9
The value of -j is 9.
<u>Part 8:</u>
Given algebraic expression is:
j = -9
Now we have to determine the value of -(-j).
- (-j) = - [-(-9)] = -9
The value of -(-j) is -9.
<u>Part 9:</u>
Given algebraic expression is:
j = -9
Now we have to determine the value of (-j)(-j).
(-j)(-j) = [- (-9)] × [- (-9)] = 9 × 9 = 81
The value of (-j)(-j) is 81.
