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stepladder [879]
2 years ago
9

I need help with 9and 10 pleas

Mathematics
1 answer:
sergejj [24]2 years ago
8 0
9 is D
10 is either a or b
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Simplify open parentheses x to the 2 third power close parentheses to the 4 fifths power.
MissTica
X to the 8/15 power. When you have a power raised to another power, you multiply the exponents.
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3 years ago
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above swimming pool is leaking after 1/2 hour the pool has lead 7/8 of a gallon of water how many gallons of water per hour is a
jekas [21]
Do a proportion. X/7/8=1/1/2. 7/8 x 1= 7/8. Now do 7/8 divided by 1/2. To do this multiply 7/8 by the reciprocal of 1/2 which is 2/1. 7 x 2= 14 and 8 x 1=8. Improper fraction is 14/8. It is 1 6/8 as a mixed number which is simplified to 1 3/4. Answer is 1 3/4
7 0
2 years ago
If sin θ = 2 over 7 and tan θ > 0, what is the value of cos θ?
sergey [27]
Sin θ = 2 / 7
tan θ > 0
cos θ = ?

sin θ = opposite / hypotenuse
tan θ = opposite / adjacent
cos θ = adjacent / hypotenuse

short leg = opposite = 2
hypotenuse = 7
long leg = adjacent = ?

adjacent = √(7² - 2²)
adjacent = √(49 - 4)
adjacent = √45
adjacent = √9 * 5
adjacent = 3 √5

cos θ = adjacent / hypotenuse
cos θ = 3√5 / 7
6 0
3 years ago
In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=
just olya [345]

Answer:

See Below.

Step-by-step explanation:

Statements:                                                           Reasons:

\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}      Given

\displaystyle 2) \text{ } m \angle PAB = 60                                                     Definition of equilateral.

3)\text{ } m \angle QAC = 60                                                     Definition of equilateral.

4)\text{ } m\angle PAB = m\angle QAC                                          Substitution

5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC                       Angle Addition

\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC                       Angle Addition

7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC                       Substitution

\displaystyle 8)\text{ } m\angle PAC=m\angle QAB                                         Substitution

9)\text{ } PA=BA                                                          Definition of equilateral

10)\text{ } AC=AQ                                                        Definition of equilateral

\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ                                            Side-Angle-Side Congruence*

\displaystyle 12)\text{ } PC=BQ                                                        CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

6 0
2 years ago
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Find an equation of the line that has the given slope and contains the given point. m=7/3 (1,6)
iris [78.8K]

The point-slope form:

y-y_1=m(x-x_1)

We have the point (1, 6) and the slope m = 7/3. Substitute:

y-6=\dfrac{7}{3}(x-1)      <em>use distributive property</em>

y-6=\dfrac{7}{3}x-\dfrac{7}{3}          <em>add 6 to both sides</em>

y=\dfrac{7}{3}x+\dfrac{11}{3}        <em>multiply both sides by 3</em>

3y=7x+11           <em>subtract 7x from both sides</em>

-7x+3y=11         <em>change the signs</em>

7x-3y=-11

Answer:

point-slope form: y-6=\dfrac{7}{3}(x-1)

slope-intercept form: y=\dfrac{7}{3}x+\dfrac{11}{3}

standard form: 7x-3y=-11

5 0
2 years ago
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