Let t be time in hours.
Train A travels at 100 km per hour, so after t hours it will be 100t km from the station.
Train B travels at 160 km per hour, but it leaves the station one and a half hours later than train A, so its time is (t-1.5) hours. After (t-1.5) hours it will be 160(t-1.5) km from the station.
Train B will overtake train A when their distances from the station are equal.

Train B will overtake train A after 4 hours since train A left the station. It left the station at 8:00, so train B will overtake it at
12:00.
Answer:
I think it would be B.
Step-by-step explanation:
I'm not 100% sure though.
Length (L): L
width (w): (2/3)L
Perimeter (P) = 2L + 2w
290 = 2(L) + 2(2/3)(L)
870 = 6L + 4L
870 = 10L
87 = L
width (w): (2/3)L = (2/3)(87) = 2(29) = 58
Answer: width = 58 ft, length = 87 ft
Answer:
x = -3/2, 1
Step-by-step explanation:
1. Use Rule of One
2. Take out the constants
3. Simplify 6/3 to 2
4. Use the product rule
5. Simplify
6. Move all terms to one side
7. Simplify
8. Split the second term
9. Factor out the common terms
10. Factor out the common term (again)
11. Solve for x
It helps you determine the characteristics of the plot/graph. I am not sure so it is your choose.