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2 years ago

I need help ASAP please (transforming functions)

Mathematics

2 answers:

Yuki888 [10]2 years ago

7 0

Answer:

okay look at it this way:

Step-by-step explanation:

when you use a mirror and you look at the shape on both sides then you will see the -x which is basically on the same side but just a minus instead. Soo let's say you have to graph a coordinate of (2,4) y=2 and x=4 si you have to graph the normal plots and when you put it in the opposite sides the thing you only did was you just made a reflection of the shape just negative instead. hope you understand what I'm saying.

(reflective)

SSSSS [86.1K]2 years ago

7 0

Answer:

D: No Change

Step-by-step explanation:

Because "x" is inside of the absolute value bars("| |"), the negative is canceled out. The graph maintains a positive "V" look.

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What is an equation of the line that passes through the point ( 6 , − 2 ) (6,−2) and is perpendicular to the line 6 x + y = 2 6x

Diano4ka-milaya [45]

Answer:

An equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

$y=\frac{1}{6}x-3$

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

Given the line

6x+y=2

Simplifying the equation to write into the slope-intercept form

y = -6x+2

So, the slope = -6

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

Thus, the slope of the perpendicular line will be: -1/-6 = 1/6

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 1/6 and the point (6, -2)

$y-\left(-2\right)=\frac{1}{6}\left(x-6\right)$

$y+2=\frac{1}{6}\left(x-6\right)$

subtract 2 from both sides

$y+2-2=\frac{1}{6}\left(x-6\right)-2$

$y=\frac{1}{6}x-3$

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

$y=\frac{1}{6}x-3$

5 0

2 years ago

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0

3 years ago

Find the accumulated value of an investment of 12,000 at 8 % compounded semiannually for 11 years

AleksAgata [21]

The "compound amount" formula is A = P(1+r/n)^(nt),
where P=original investment, r=interest rate as a decimal fraction; n=number of compounding periods, and t=number of years.

Then A = $12000 * (1+0.08/2)^(2*11)
= $12000(1.04)^(22) = $28,439.03 (answer)

4 0

2 years ago

If there is 360 grams of radioactive material with a half-life of 8 hours, how much of the radioactive material will be left aft

AnnZ [28]

22.5 grams : Exponential

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3 years ago

X + 3y = -3 solve for Y (ex. y= 3 + 5x

AnnyKZ [126]

Answer:

y = -1/3x - 1

Step-by-step explanation:

Let's solve for y.

Step 1: Add -x to both sides.

x+3y+−x=−3+−x

3y=−x−3

Step 2: Divide both sides by 3.

y=-1/3x-1

$\frac{-1}{3} x-1$

3 0

2 years ago