The weight of each one of the five little girls if taken separately is 242.4 lb.
<h3>
Weight of each girl when taken separately</h3>
The weight of each girl can be determined from the average weight of the girls.
Weight of each girl = (Total weight) / number of girls
W = (129 + 125 + 124 + 123 + 122 + 121 + 120 + 118 + 116 + 114)/5
W = 1,212/5
W = 242.4 lb
Thus, the weight of each one of the five little girls if taken separately is 242.4.
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Answer:
x = √2, y = 2
Step-by-step explanation:
You know that the sides of an isosceles right triangle are equal in length, so ...
x = √2 . . . . same as the given side
You also know that the hypotenuse is √2 times as long as one side, so ...
y = √2·√2
y = 2
Answer:
Since EF bisects ∠DEF, we know that EF splits ∠DEF in 2 halves from the word 'bisects', which can be written as 'bi- sects' , where bi means 2 and sects means sections
Hence, ∠DEG = ∠GEF --------------(1)
We are given the measure of these angles:
∠DEG = 3x - 4
∠GEF = x + 13
Now, replacing the values in (1):
3x - 4 = x + 13
2x = 17
x = 17/2
Now, finding the measure of ∠DEF:
∠DEF = ∠DEG + ∠GEF
∠DEF = 3x - 4 + x + 13
∠DEF = (51 / 2) - 4 + (17/2) + 13 (x = 17/2)
∠DEF = 34 - 4 + 13
∠DEF = 43°
Answer:
An equation in standard form for the line is:
Step-by-step explanation:
Given the points
The slope between two points
Writing the equation in point-slope form
As the point-slope form of the line equation is defined by
Putting the point (-2, -1) and the slope m=1 in the line equation
Writing the equation in the standard form form
As we know that the equation in the standard form is
where x and y are variables and A, B and C are constants
so
Therefore, an equation in standard form for the line is:
Answer:
Option A -The curves intersect at approximately x = 0.46.
