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sergiy2304 [10]
3 years ago
5

How to factor 3x^2-10x-8?

Mathematics
2 answers:
Soloha48 [4]3 years ago
4 0

<em>answer \\(x - 4)(3x + 2)  \\ solution \\  {3x}^{2}  - 10x - 8 \\  =  {3x}^{2}  - (12 - 2)x - 8 \\  =  {3x}^{2}  - 12x + 2x - 8 \\  = 3x(x - 4) + 2(x - 4) \\  = (x - 4)(3x  + 2) \\ hope \: it \: helps</em>

Elan Coil [88]3 years ago
3 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
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7 0
3 years ago
RS = 4x – 9, ST = 19, RT = 80 – 14<br><br> Equation:<br><br> 82 – 14<br><br> RS<br><br> RT
algol13

Step-by-step explanation:

The expressions are not properly written

Given

RS = 4x – 9

ST = 19

RT = 8x – 14

Based on the given parameters, the addition postulate below is true

RS+ST = RT

Substitute

4x-9+19 = 8x-14

collect like terms

4x-8x = -14-19+9

-4x = -33+9

-4x = -24

x = -24/-4

x = 6

Get RS:

RS = 4x-9

RS = 4(6)- 9

RS = 24-9

RS = 15

Get RT:

RT = 8x - 14

RT = 8(6)-14

RT = 48-14

RT = 34

4 0
3 years ago
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