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3 years ago

Please help me out if you can :)

Mathematics

1 answer:

nexus9112 [7]3 years ago

3 0

$\frac{29}{10} = x + \frac{1}{x} \\ 29 = 10x + \frac{10}{x} \\ 10x - 29 + \frac{10}{x} = 0 \\ 10 {x}^{2} - 29x + 10 = 0 \\ \frac{29 + \sqrt{841 - 400} }{20} = x \\ \frac{29 + \sqrt{441} }{20} = x \\ \frac{29 + 21}{20} = \frac{50}{20} = 2 \frac{1}{2} = x \\ or \\ \frac{29 - \sqrt{841 - 400} }{20} = x \\ \frac{29 - \sqrt{441} }{20} = x \\ \frac{29 - 21}{20} = \frac{8}{20} = \frac{2}{5} = x$

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2 years ago

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Answer:

We conclude that:

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Step-by-step explanation:

Given the equation

$\left(x-8\right)^2\:+\:16$

First, solve (x - 8)²

Apply Perfect Square formula: (a - b)² = a² - 2ab + b²

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so the expression becomes

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$\left(x-8\right)^2+16=x^2-16x+80$

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2 years ago

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Hi there!

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