Points (4,2) and (6, 10)
Eqn:
y - y = m(x - x)
y - 2 = [(2-10)/(4-6)] (x - 4)
y - 2 = (-8/-2) (x - 4)
y - 2 = 4(x-4)
y - 2 = 4x - 16
y - 2 + 2 = 4x - 16 + 2
y = 4x - 14
Therefore the slope (m) would be 4 and the y intercept (b) would be -14.
I’m guessing you meant central tendency.
I’d say the mean is the best measure for period 2. This is because it doesn’t have any extremely low or high values which could distort the mean value.
If it did ie. 8, then I would choose median as it is less affected by anomalous results
Step-by-step explanation:
we know,

Therefore, nth term of a given gp is
16a
Hi...the answer is b.. I would recommend plot graph and find the gradient.... then use the point formula
K=14 i think thats right im not sure