Question

Show that 2x^2+5x-58=0

Answer 1

The two values of x are -6.77 and 4.27

Explanation:

Given:

2x² + 5x - 58 = 0

Solving the equation further:

For quadratic equation:

$x = -b +- \frac{\sqrt{b^2-4ac} }{2a}$

where,

a = 2

b = 5

c = -58

Substituting the values in the equation we get:

$x = -5 + \frac{\sqrt{5^2-4X2X-58} }{2 X 2} \\\\x = -5 +- \frac{\sqrt{489} }{4} \\\\x = 4.27, -6.77$

The two values of x are -6.77 and 4.27