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rodikova [14]
3 years ago
14

Show that 2x^2+5x-58=0

Mathematics
1 answer:
olganol [36]3 years ago
6 0

The two values of x are -6.77 and 4.27

<u>Explanation:</u>

Given:

2x² + 5x - 58 = 0

Solving the equation further:

For quadratic equation:

x = -b +- \frac{\sqrt{b^2-4ac} }{2a}

where,

a = 2

b = 5

c = -58

Substituting the values in the equation we get:

x = -5 + \frac{\sqrt{5^2-4X2X-58} }{2 X 2} \\\\x = -5 +- \frac{\sqrt{489} }{4} \\\\x = 4.27, -6.77

The two values of x are -6.77 and 4.27

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