Find the area of the triangle ABC given angle A = 60°, b = 2, and c = √2.

2 answers:

7 0

If you know 2 sides and an included angle, the area formula is:

Area = ½ • side 1 • sine (A) • side 2

Area = ½ • 2 * sine (60) * sq root (2)

Area =sine (60) * sq root (2)

The sine of 60 degrees = sq root (3) / 2

Area = sq root (6) / 2

7nadin3 [17]2 years ago

4 0

Answer:

6/2

Step-by-step explanation:

i got this right

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levacccp [35]

Answer:

find the value of x that makes the denominator zero: x = 7

Step-by-step explanation:

A vertical asymptote shows up where the denominator is zero. As the denominator gets closer to zero, the function value gets larger without bound (unless there is a numerator factor that cancels the one in the denominator).

To find the value of x at the vertical asymptote, solve the equation ...

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