Question

Find the area of the triangle ABC given angle A = 60°, b = 2, and c = √2.

Answer 1

If you know 2 sides and an included angle, the area formula is:

Area = ½ • side 1 • sine (A) • side 2

Area = ½ • 2 * sine (60) * sq root (2)

Area =sine (60) * sq root (2)

The sine of 60 degrees = sq root (3) / 2

Area = sq root (6) / 2

Answer 2

Answer:

6/2

Step-by-step explanation:

i got this right