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vagabundo [1.1K]
3 years ago
5

Find the area of the triangle ABC given angle A = 60°, b = 2, and c = √2.

Mathematics
2 answers:
Irina18 [472]3 years ago
7 0
<span>If you know 2 sides and an included angle, the area formula is:
</span>
<span>Area = ½ • side 1 • sine (A) • side 2
</span>
<span>Area = ½ • 2 * sine (60) * sq root (2)
</span>
<span>Area =sine (60) * sq root (2)
</span>
<span>The sine of 60 degrees = sq root (3) / 2
</span>
Area = sq root (6) / 2

7nadin3 [17]3 years ago
4 0

Answer:

6/2

Step-by-step explanation:

i got this right

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One hamburger and one coke cost $3.20. Three hamburgers and one coke cost $8.00. Find the cost of one hamburger.
Varvara68 [4.7K]

Answer:

$0.80

Step-by-step explanation:

-3 (1x + 1y = 3.2)

3x + 1y = 8

----------------

-3x - 3y = -9.6

+

3x + 1 y = 8

-------------------

0x -2y = -1.6

÷ -2

-----------------

y = 0.8

one hamburger costs $0.80

5 0
3 years ago
Read 2 more answers
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
3 years ago
Read 2 more answers
When starting your credit history, a low-credit-limit, high-interest-rate credit card should be paid
ale4655 [162]

Answer:

to the full amount

Step-by-step explanation:

3 0
3 years ago
18x - 77=1<br> X - 7y=-33
SIZIF [17.4K]

Answer:

x=-33+7y

then putting value of x

18(-33+7y)-77=1

-594+126y-77=1

-671+126y=1

126y=670

y=670/126

4 0
2 years ago
Elaborati un desen : punctul m este mijlocul bazei triunghiuluibisoscel abc
blondinia [14]
Uh .. Nu vorbesc limba română, dar am încercat meu cel mai bun pentru a face această întrebare.

Teorema: Fie ABC un triunghi isoscel cu AB = AC. Fie M denota punctul central al BC (adică, M este punctul pe BC pentru care MB = MC). Apoi
a) Triangle ABM este congruent cu ACM triunghi.
b) Unghi ABC = ACB Angle (unghiuri de bază sunt egale)
c) Unghi AMB = Unghi AMC = unghi drept.
d) Unghi BAM = unghiul CAM


Corolar: Prin urmare, din aceste fapte și definițiile:
Ray AM este unghiul bisectoarea unghiului BAC.Linia AM este altitudinea triunghiului ABC, prin A.Linia AM este mediatoare BSegmentul AM este mediana triunghiului ABC, prin A.Dovada # 1 din Teorema (după B & B)
Lasa bisectoarea unghiului de BAC se intersectează segmentul BC la punctul D.
Din moment ce raza AD este unghiul bisectoare, unghiul BAD = unghiul CAD.Segmentul AD = AD = sine.De asemenea, AB = AC deoarece triunghiul este isoscel.Astfel, triunghiul BAD este congruent cu CAD de SAS (side-unghi-side).
8 0
3 years ago
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