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son4ous [18]
3 years ago
7

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Mathematics
1 answer:
expeople1 [14]3 years ago
8 0

As there is no any equation, I can't answer your question.

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What is the slope of the line?<br><br> A. 2<br> B. -2<br> C. 1/2<br> D. -1/2
iogann1982 [59]

slope m = - 2 → B

calculate m using the ' gradient formula '

m = (y₂ - y₁)/(x₂ - x₁)

choosing 2 'clear ' coordinates from the graph of the line

(x₁, y₁) = (0, 7) and (x₂, y₂) = (7, - 5\frac{(- 5 - 7)}{(6 - 0)}) = \frac{- 12}{6} = - 2


m =

3 0
3 years ago
The difference of the product of 3 and 6 minus the quotient of 6 divided by 2​
Mandarinka [93]
Answer is :
(6*3)-(6/2)
8 0
3 years ago
Consider the differential equation y'' − y' − 30y = 0. Verify that the functions e−5x and e6x form a fundamental set of solution
Alex Ar [27]

Answer:

Step-by-step explanation:

We have to take the derivatives for both functions and replace in the differential equation. Hence

for y=e^{-5x}:

y(x)=e^{-5x}\\y'(x)=-5e^{-5x}\\y''(x)=25e^{-5x}\\

for y=e^{6x}:

y(x)=e^{6x}\\y'(x)=6e^{6x}\\y''(x)=36e^{6x}\\

Now we replace in the differential equation  y'' − y' − 30y = 0

for y=e^{-5x}:

25e^{-5x}+5e^{-5x}-30e^{-5x}=0\\25+5-30=0

for y=e^{6x}:

36e^{6x}-6e^{6x}-30=0\\36-6+30=0

Now, to know if both function are linearly independent we calculate the Wronskian

W(f,g)=fg'-f'g

W(e^{-5x},e^{6x})=(e^{-5x})(6e^{6x})-(-5e^{-5x})(e^{6x})\neq 0

I hope this is useful for you

Best regard

7 0
3 years ago
Combine the terms in the following expressions.<br> a. 10x-4x
Ilya [14]

Answer:

6x

Step-by-step explanation:

Step 1:

10x - 4x

Answer:

6x

Hope This Helps :)

7 0
3 years ago
WILL GIVE BRAINLIEST
sveticcg [70]
The answer is 2x15 which is 30ft
3 0
2 years ago
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