Multiply the second fraction by three.
4/9 + 3/9 = 7/9
A= 3
b= 4
=3.14(a^2 + ab)
substitute the given a & b values in expression
=3.14((3)^2 + (3*4))
multiply inside parentheses
=3.14(9 + 12)
add inside parentheses
=3.14(21)
multiply
=65.94
ANSWER: 65.94
Hope this helps! :)
Answer:
Step-by-step explanation:
Given that
Sample size = n = 8: sample mean = 36.5 and s = sample std dev = 7.4 minutes
98% CI using t = (28.7, 44.3) with margin of error as 7.8
Now if sigma = population std dev is known we use Z critical value
Margin of error = 2.33*8.7/\sqrt 8 = 7.167
CI = (36.5 ±7.167)
This is not wider than that used using t distribution
The margin of error of u is ___7.167
98% confidence interval using the standard normal distribution is (29.333__,43.667__)
d)the confidence interval found using the standard normal distrubution is narrower than the confidence interval found using the students t-distribution
