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3 years ago

HELPPPPP PLEASE!!

1 answer:

7 0

The answer is D.
To solve it, you have to add the fractions.
1) Since it is in mixed numbers, you have to turn the fractions to improper.
 2 1/2 + 1 1/4 = 5/2 + 5/4

2) Next find the lowest common multiples of the denominators( 2 and 4)
2: 2, 4
 4: 4

3) Solve
 5 x 2
2 x 2 = 10/4 10/4 + 5/4 = 15/4 <--make sure you only add the nominators after you find the common multiples.

4) Turn into a proper fraction
15/4 = 3 3/4

There are 3 3/4 gallons of paint all together. Therefore, answer D is correct.

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Please help asap! the problem is in the picture

ladessa [460]

Given:

$AB=6\ BC=r,\ CD=r,\ AD=12$ .

To find:

The value of r.

Solution:

We have,

$AB=6\ BC=r,\ CD=r,\ AD=12$ .

We know that the radius is perpendicular to the tangent at the point of tangency

AD is the tangent and CD is the radius. So, CD is perpendicular to AD at point D, i.e., $m\angle D=90^\circ$ .

Using Pythagoras theorem, we get

$AC^2=AD^2+CD^2$

$(6+r)^2=12^2+r^2$

$36+12r+r^2=144+r^2$

$12r=144+r^2-36-r^2$

On further simplification, we get

$12r=108$

$r=\dfrac{108}{12}$

$r=9$

Therefore, the value of r is 9.

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2 years ago

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Answer:

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Step-by-step explanation:

it is a vertical line on zero and this is 1st grade level math

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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This solution to this problem is predicated on the fact that the circumference is just: $2\pir$ . A straight line going through the center of the garden would actually be the diameter, which is well known to be two times the radius of the circle, so we can say that the circumference is just:

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So, solving for both the radius and the diameter gives us:

$d\pi=8xy^2\pi\\ d=8xy^2\\ \\ 2\pi r=8xy^2\pi\\ r=4xy^2$

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$A=\pi r^2 \implies \\ A=\pi (4xy^2)^2\implies \\ A= 16\pi x^2y^4$

So, we have found our area( $16 \pi x^2 y^4$ ) and the problem is done.

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3 years ago