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Savatey [412]
3 years ago
10

Ramon wants to make an acute triangle with three pieces of wood. So far, he has cut wood lengths of 7 inches and 3 inches. He st

ill needs to cut the longest side. What length must the longest side be in order for the triangle to be acute? exactly StartRoot 58 EndRoot inches greater than StartRoot 58 EndRoot inches but less than 10 inches less than StartRoot 58 EndRoot inches but greater than 7 inches not enough information given
Mathematics
2 answers:
MrMuchimi3 years ago
7 0

Answer:     less than StartRoot 58 EndRoot inches but greater than 7 inches

Step-by-step explanation

o-na [289]3 years ago
5 0

Answer: Exactly square root 58 inches

Step-by-step explanation: The dimensions given for the right angled triangle are 7 inches and 3 inches respectively. The third side is yet unknown. However what we know is that a right angled triangle can be solved by using the Pythagoras theorem which states that,

AC^2 = AB^2 + BC^2

Where AC is the longest side. The question requires us to calculate the longest side and with the other two sides already known, the Pythagoras theorem now becomes,

AC^2 = 7^2 + 3^2

AC^2 = 49 + 9

AC^2 = 58

Add the square root sign to both sides of the equation

AC = square root 58 inches

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According to a study conducted by the Gallup Organization, the the proportion of Americans who are afraid to fly is 0.10. A rand
notsponge [240]

Answer: 0.1457

Step-by-step explanation:

Let p be the population proportion.

Given: The proportion of Americans who are afraid to fly is 0.10.

i.e. p= 0.10

Sample size : n= 1100

Sample proportion of Americans who are afraid to fly =\hat{p}=\dfrac{121}{1100}=0.11

We assume that the population is normally distributed

Now, the probability that the sample proportion is more than 0.11:

P(\hat{p}>0.11)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.11-0.10}{\sqrt{\dfrac{0.10(0.90)}{1100}}})\\\\=P(z>\dfrac{0.01}{0.0090453})\ \ \ [\because z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}} ]\\\\=P(z>1.1055)\\\\=1-P(z\leq1.055)\\\\=1-0.8543=0.1457\ \ \ [\text{using z-table}]

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3 0
3 years ago
Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...
katovenus [111]

Answer:

  • a_{12}=-244140625

Step-by-step explanation:

Considering the geometric sequence

5,-25,\:125,\:...

a_1=5

As the common ratio 'r' between consecutive terms is constant.

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

r=\frac{-25}{5}=-5

r=\frac{125}{-25}=-5

The general term of a geometric sequence is given by the formula:  

a_n=a_1\cdot \:r^{n-1}

where a_1 is the initial term and r the common ratio.

Putting n = 12 , r = -5 and a_1=5 in the general term of a geometric sequence to determine the 12th term of the sequence.

a_n=a_1\cdot \:r^{n-1}

a_n=5\left(-5\right)^{n-1}

a_{12}=5\left(-5\right)^{12-1}

      =5\left(-5^{11}\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

       =-5\cdot \:5^{11}

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

        =-5^{1+11}     ∵ 5\cdot \:5^{11}=\:5^{1+11}

        =-244140625

Therefore,

  • a_{12}=-244140625
6 0
3 years ago
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