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Free_Kalibri [48]

3 years ago

11

An equation is given: 16meters−1,000centimeters=?

1 answer:

torisob [31]3 years ago

6 0

1 meter = 100 cm
16×100=1600
1600-1000=600

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How to graph 30=1x+9y

statuscvo [17]

<span>Simplifying graph + -1x + -9y = 8 Solving aghpr + -1x + -9y = 8 Solving for variable 'a'. Move all terms containing a to the left, all other terms to the right. Add 'x' to each side of the equation.</span>

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If u(x) = x^5 - x^4 + x^2 and v (x) = -x^2 which expression is equivalent to ( u/ v) (x)

yawa3891 [41]

Answer:

$(u/v)(x)=-x^{3}+x^{2}-1$

Step-by-step explanation:

You have the following functions:

$u(x)=x^{5}-x^{4}+x^{2}\\v(x)=-x^{2}$

Therefore $(u/v)(x)$ indicates that you must divide both functions, as you can see below:

$(u/v)(x)=\frac{x^{5}-x^{4}+x^{2}}{-x^{2}}$

Simplify it. Therefore, you obtain:

$(u/v)(x)=\frac{x^{5}-x^{4}+x^{2}}{-x^{2}}\\\\(u/v)(x)=-x^{3}+x^{2}-1$

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3 years ago

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. He has $75 in his checking account and has already spent $53.86 on food. Which inequality represents how much Jeremy has left

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3 years ago

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blagie [28]

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3 years ago

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Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi

bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

$L = L_{1} + L_{2} + L_{3}$

In which $L_{1}, L_{2}$ and $L_{3}$ are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

$E = E_{1} + E_{2} + E_{3}$

In which $E_{1},E_{2}$ and $E_{3}$ are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

$6*0.050mg = 0.30mg$ of levonorgestrel and $6*0.030mg = 0.18mg$ of ethinyl estradiol are taken.

So $L_{1} = 0.30$ and $E_{1} = 0.18$

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

$5*0.075mg = 0.375mg$ of levonorgestrel and $5*0.040mg = 0.20mg$ of ethinyl estradiol are taken.

So $L_{2} = 0.375$ and $E_{2} = 0.20$

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

$10*0.125mg = 1.25mg$ of levonorgestrel and $10*0.030mg = 0.30mg$ of ethinyl estradiol are taken.

So $L_{3} = 1.25$ and $E_{3} = 0.30$

The total milligrams of levonorgestrel is:

$L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925$

The total milligrams of ethinyl estradiol is:

$E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68$

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0

3 years ago