Bearing in mind that a rectangle has a perimeter of length + length + width + width.
P = perimeter
L = length
x=width
P = 2L + 2x
P = 2(L+x) <==== perimeter of the base of the box.
check the picture below.
Answer:
x-axis = ![\frac{9\pi }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B9%5Cpi%20%7D%7B2%7D)
y-axis = ![\frac{4\pi }{5} .3(^{\frac{5}{2} } )](https://tex.z-dn.net/?f=%5Cfrac%7B4%5Cpi%20%7D%7B5%7D%20.3%28%5E%7B%5Cfrac%7B5%7D%7B2%7D%20%7D%20%29)
Line x =3 : ![\frac{44\sqrt{3} }{5} \pi](https://tex.z-dn.net/?f=%5Cfrac%7B44%5Csqrt%7B3%7D%20%7D%7B5%7D%20%5Cpi)
Line x = 6 : ![\frac{84\sqrt{3}\pi }{5}](https://tex.z-dn.net/?f=%5Cfrac%7B84%5Csqrt%7B3%7D%5Cpi%20%20%7D%7B5%7D)
Step-by-step explanation:
Given lines : y = √x
y = 0
x = 3
To determine the volumes generated we will use the disk method for each of the lines,
attached below is the detailed solution for line x =3 , same procedure will be repeated for each value of x and y to obtain the given results
The volume generated ( x axis )
= ![\frac{9\pi }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B9%5Cpi%20%7D%7B2%7D)
volume generated ( y _axis )
= ![\frac{4\pi }{5} .3(^{\frac{5}{2} } )](https://tex.z-dn.net/?f=%5Cfrac%7B4%5Cpi%20%7D%7B5%7D%20.3%28%5E%7B%5Cfrac%7B5%7D%7B2%7D%20%7D%20%29)
Volume about x = 3
= ![\frac{44\sqrt{3}\pi }{5}](https://tex.z-dn.net/?f=%5Cfrac%7B44%5Csqrt%7B3%7D%5Cpi%20%20%7D%7B5%7D)
Volume about x = 6
= ![\frac{84\sqrt{3}\pi }{5}](https://tex.z-dn.net/?f=%5Cfrac%7B84%5Csqrt%7B3%7D%5Cpi%20%20%7D%7B5%7D)
Answer:
5/7
Step-by-step explanation:
Answer:
-2
Step-by-step explanation:
Solve for x. so first u would subtract 25 from 25 and 298. 25 will be crossed out so now u are left with 13x<273. to solve that, divide 13 on both sides. 13 would be crossed or so now u are left with x<13. that means x can equal anything less than 13. idk about the rest, i think u can do it. :)