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Elina [12.6K]
3 years ago
7

If CE=20, find DE. CD= 5x+1, DE= 3x+3

Mathematics
1 answer:
ladessa [460]3 years ago
6 0
The answer is 9 because
5x+1+3x+3=20
x=2
3(2)+3
9
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Find two positive numbers satisfying the given requirements. The product is 432 and the sum of the first plus three times the se
kogti [31]

Answer:

<h3>36 and 12</h3>

Step-by-step explanation:

Let the two positive integers be x and y.

If their product is 432, then

xy = 432 ......... 1

Also if the sum of the first plus three times the second is a minimum, then;

p(x) = x + 3y

From 1;

y = 432/x ..... 3

Substitute 3 into 2;

p(x) = x+3y

p(x)= x + 3(432/x)

p(x) = x + 1296/x

Since the expression is at minimum when dp(x)/dx = 0

dp/dx = 1 + (-1296)/x²

dp/dx = 1  -1296/x²

0 =  1  -1296/x²

0 = (x²-1296)/x²

cross multiply

0 = x²-1296

x² = 1296

x = √1296

x = 36

Since xy = 432

36y = 432

y = 432/36

y = 12

Hence the two positive numbers are 36 and 12

4 0
2 years ago
A certain recipe calls for 2 2/3 cups of sugar. If the recipe is to be doubled, how much sugar should be used?
lawyer [7]
You should double the sugar as well, but first let us simplify the 2 2/3 to become 8/3, then double that to have 16/3,
Which is then can be simplified to 5 1/3
6 0
3 years ago
Read 2 more answers
If X=3, What is the area of a triangle with sides, 6x ,7x, and 21x? A.117 in² B.378 in² C.189 in² D. 58.5 in²
AURORKA [14]

Answer:

The given sides does not form a triangle

Step-by-step explanation:

The given sides does not form a triangle

We know the triangle property which states that the sum of any two sides of the triangle should be greater than the third side.

Here given th esides of the triangle are 6x,7x,21x

6x+7x=13x < 21x

for any value of x the above equation does not satisfy.

8 0
3 years ago
Combine and simplify the following radical expresión.
Kobotan [32]

Answer:

12(3√6)

Step-by-step explanation:

6(3√12)(3√2)

= 6(3√4√3)(3√2)

= 12(3√3)(3√2)

= 12(3√6)

4 0
2 years ago
Read 2 more answers
Use the distance formula, show that the points (4,0), (2,1), and (-1,-5) form the vertices of a right triangle
mario62 [17]

Step-by-step explanation:

The distance formula between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points.

A(4,\ 0),\ B(2,\ 1),\ C(-1,\ -5)\\\\AB=\sqrt{(2-4)^2+(1-0)^2}=\sqrt{(-2)^2+1^2}=\sqrt{4+1}=\sqrt5\\\\AC=\sqrt{(-1-4)^2+(-5-0)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=\sqrt{50}\\\\BC=\sqrt{(-1-2)^2+(-5-1)^2}=\sqrt{(-3)^2+(-6)^2}=\sqrt{9+36}=\sqrt{45}

If a ≤ b < c are the sides of the right triangle, then

a² + b² = c²

\sqrt5

used (\sqrt{a})^2=a for a ≥ 0.

AB^2+BC^2=AC^2 therefore ΔABC is a right triangle.

6 0
3 years ago
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