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professor190 [17]
3 years ago
5

angle 1 is a supplement of angle 2 and a compliment of angle 3 and angle 1= 68 degrees what is angle 2 - angle 3

Mathematics
1 answer:
Murljashka [212]3 years ago
3 0

Answer:

90

Step-by-step explanation:

Angle 2 = 180 - 68 = 112

Angle 3 = 90 - 68 = 22

Angle 2 - Angle 3 = 112 - 22 = 90

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If p and q are both true, then which of the following statements has the same truth-value as ~p → q?
olganol [36]

If p and q are both true, then

\neg p \implies q

is an implication of the form

F \implies T

which is true, because every implication starting with false is true, i.e.

F \implies T = T,\quad F \implies F = T

So, we're looking for an expression evaluating to true. Let's see what we have:

A) is an AND proposition. Logical AND is true only if both parts are true. So, you have

\neg P \land \neg Q = F \land F = F

So it's not the right option.

B) is an OR proposition. Logical OR is true whenever one of the two parts is true. So, you have

\neg P \lor\neg Q = F \lor F = F

So it's not the right option.

C) is again an AND proposition. You have

P \land \neg Q = T \land F = F

So this is not the right option.

D) Finally, the last one is again an implication, and again it starts with false:

\neg Q \implies P = F \implies T = T

So this is true, and thus is the correct option.

8 0
3 years ago
HELP PLS- 50pts!!! (This is Linear programming)- The amphitheater has two types of tickets available, reserved seats and lawn se
Alenkinab [10]

The Maximum profit occurs when 20,000 reserved seats are sold and the profit is $1,300,000



3 0
3 years ago
Can someone hep me on this
Pavel [41]
5x+4y= $35
x= daisies and y=roses
3x+6y=$39
7 0
3 years ago
Help FAST PLZ!!! marking brainliest!
ss7ja [257]

Answer:

After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.

Step-by-step explanation:

hope this helps

5 0
2 years ago
How do you do this problem?
aev [14]

f(x) = (x - 4)^2 - 1

g(x) = -(1/4) ( x - 4)^2 + 4

both the x and y values have to be the same. Start with the y values

f(x) = g(x)

(x - 4)^2 - 1 = -(1/4) (x - 4)^2 + 4 Add 1 to both sides.

(x - 4)^2 = -(1/4) (x - 4)^2 + 5 Add 1/4(x - 4)^2 to both sides.

(5/4) (x - 4)^2 = 5 Divide by 5/4 on both sides.

(x - 4)^2 = 5//(5/4)

(x - 4)^2 = (5/1)//5/4 Invert the second fraction and multiply

(x - 4)^2 = 5/1 * 4/5

(x - 4)^2 = 4 The 5s cancel

(x - 4)^2 = 4 Take the square root of both sides.

(x - 4) = +/- 2 Add 4 to each answer. Start with +2 on the right.

x - 4 + 4 = 2 + 4

x = 4 + 2 = 6

The x value that makes f(x)- g(x) = 0 is x = 6 The point is (6,3) answer.

Answer C.

================================================

You do not need this next part. It is just for completeness.

x - 4 = - 2

x = 4 -2

x = 2

What are the y values for these 2 x values?

y = (x - 4)^2 - 1

y = (6 - 4)^2 - 1

y = 4 - 1

y = 3

The point where f(x) - g(x) = 0 is (6,3) <<<<<< Answer 1

The second point is

y = (x - 4)^2 - 1

y = (2 - 4)^2 - 1

y = (-2)^2 - 1

y = 4 - 1

y = 3

The second point is (2,3). Answer 2

Note the y values are the same. You might expect that.

3 0
3 years ago
Read 2 more answers
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