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professor190 [17]
3 years ago
5

angle 1 is a supplement of angle 2 and a compliment of angle 3 and angle 1= 68 degrees what is angle 2 - angle 3

Mathematics
1 answer:
Murljashka [212]3 years ago
3 0

Answer:

90

Step-by-step explanation:

Angle 2 = 180 - 68 = 112

Angle 3 = 90 - 68 = 22

Angle 2 - Angle 3 = 112 - 22 = 90

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Rapido porfa es para hoy.<br> Convierta 0.80 Megagramos a picogramos.
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Answer:

8 * 10^17 Picogramos

Step-by-step explanation;

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Let v1=(3,5) and v2=(-4,7) Compute the unit vectors in the direction of |v1| and |v2|?
AleksandrR [38]
By definition, the unit vector of v = (a,b) is
\hat{v} =  \frac{\vec{v}}{|v|}

Therefore,
The unit vector of v₁ = (3,5) in the direction of |v₁| s
 (3,5)/√[3² + 5²]
= (3,5)/√34

The unit vector of v₂ in the direction of |v₂| is
(-4,7)/√[(-4)² + 7²]
= (-4,7)/√65

Answer:
The unit vector of v₁ in the direction of |v₁} is ( \frac{3}{\sqrt{34}} ,  \frac{5}{\sqrt{34}} )
The unit vector of v₂ in the directin of |v₂| is
( \frac{-4}{\sqrt{65}} , \frac{7}{\sqrt{65}} )

6 0
3 years ago
Find the perimeter of the parallelogram with these vertices.
blondinia [14]

Check the picture below.

so we can say that two sides are "4" each in length, since opposite sides are equal, let's find how long the slanted sides are.

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[3 - (-4)]^2 + [5 - 2]^2}\implies d=\sqrt{(3+4)^2+3^2} \\\\\\ d=\sqrt{49+9}\implies d=\sqrt{58} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{4~~ + ~~4~~ + ~~\sqrt{58}~~ + ~~\sqrt{58}\implies 8+2\sqrt{58}}

4 0
3 years ago
On a baseball field, the pitcher’s mound is 60.5 feet from home plate. During practice, a batter hits a ball 195 feet at an angl
worty [1.4K]

In this problem, we can imagine that all the points connect to form a triangle. The three point or vertices are located on the pitcher mount, the home plate and where the outfielder catches the ball. So in this case we are given two sides of the triangle and the angle in between the two sides.

<span>With the following conditions, we can use the cosine law to solve for the unknown 3rd side. The formula is:</span>

c^2 = a^2 + b^2 – 2 a b cos θ

Where,

a = 60.5 ft

b = 195 ft

θ = 32°

Substituting the given values:

c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32

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c^2 = 21,675.56

c = 147.23 ft

<span>Therefore the outfielder throws the ball at a distance of 147.23 ft towards the home plate.</span>

8 0
3 years ago
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