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3 years ago

So I could do my homework in this app?

Mathematics

1 answer:

Bess [88]3 years ago

7 0

Yes its awesome because it helps alot on everything litterly

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A person invested $1,500 in an account growing at a rate allowing the money to

mamaluj [8]

I’m going to guess 3751? Because if it doubles every twelve years then it multiplies by .1667 every year so multiply .1667 by 12 doubles the number, so multiplying .1667 by 15 should be 3751 if rounded.

6 0

3 years ago

Read 2 more answers

A salsa recipe uses green pepper onion and tomato in the extended ratio 2:5:9

melamori03 [73]

Answer:

how does this question make sense

Step-by-step explanation:

8 0

3 years ago

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For the school play, the advance tickets cost $3, while tickets at the door cost $5. Thirty more tickets were sold at door in ad

Talja [164]

Answer:

<u>310</u> tickets were sold in advance before school pay and <u>340</u> door tickets were sold in advance.

Step-by-step explanation:

Given:

Let number of tickets sold in advance be 'x'.

Cost of advance ticket = $3

Cost of door tickets = $5

Also given:

Thirty more tickets were sold at door in advance

Hence number of door tickets sold = $x+30$

Total Money Collected = $2630

Now we can say that Total Money Collected is equal to sum of number of tickets sold in advance multiplied by Cost of advance ticket and number of door tickets sold multiplied by Cost of door tickets.

Framing in equation form we get;

$3x+(x+30)5=2630$

Solving the equation to find the value of x we get;

$3x+5x+150=2630$

Combining the like terms we get;

$3x+5x=2630-150\\\\8x= 2480$

Now Dividing 8 on both side using division property we get;

$\frac{8x}{8} =\frac{2480}{8}\\ \\x=310$

Substituting the value of x to find number of door tickets been sold.

number of door tickets sold = $x+30=310+30 =340$

Hence, <u>310</u> tickets were sold in advance before school pay and <u>340</u> door tickets were sold in advance.

8 0

3 years ago

OA=<br> Please help asap!! Thanks so much :))

Mashcka [7]

In the given diagram, the value of the dashed side of rhombus OABC is 5

<h3>Distance between two points </h3>

From the question, we are to determine the length of the dashed line (OA), in rhombus OABC

In the diagram, we can observe that the length of OA is the distance between point A and the origin (O).

Using the formula for calculating distance between two points,

d =√[(x₂-x₁)² + (y₂-y₁)²]

In the diagram,

The coordinate of the origin is (0, 0)

The coordinate of point A is (3, 4)

Thus,

x₁ = 0

x₂ = 3

y₁ = 0

y₂ = 4

Putting the parameters into the formula, we get

OA =√[(3-0)² + (4-0)²]

OA =√(3² + 4²)

OA =√(9+16)

∴ OA =√25

OA = 5

Hence, in the given diagram, the value of the dashed side of rhombus OABC is 5

Learn more on Distance between two points here: brainly.com/question/24778489

#SPJ1

5 0

2 years ago

How do I solve this problem?

Scorpion4ik [409]

Find another point (-2, -2)
Find the slope (-2-1)/(-2+3)
Insert into formula y-y1=m(x-x1)
y-1=(-3/5)(x+3)

5 0

3 years ago