Question

A line has y intercept -6 and a x-intercept - 12. what is the equation of the line

Answer 1

Answer:

$\boxed{y = -\dfrac{1}{2}x-6}}$

Step-by-step explanation:

The equation for a straight line is

y = mx + b

where m is the slope of the line and b is the y-intercept.

The line passes through the points (-12, 0) and (0, 6)

(a) Calculate the slope of the line

$\begin{array}{rcl}m & =&\dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\ & = &\dfrac{6 - 0 }{0 - (-12)}\\\\& = &\dfrac{6}{-12}\\\\& = & -\dfrac{1}{2}\\\end{array}$

(b) Write the equation

The y-intercept is at x = -6.

$\text{The equation for the line is \boxed{\mathbf{y = -\dfrac{1}{2}x-6}} }$

The diagram shows the graph of the line passing through the two intercepts.